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2 years ago

7

A function of the form f(x) = abx is modified so that the b value remains the same but the a value is increased by 2. How do the

domain and range of the new function compare to the domain and range of the original function? Check all that apply.

1 answer:

skelet666 [1.2K]2 years ago

6 0

Its stay the same by adding zero to it

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Kaleb went to a theme park with $25 to spend. He spent $5.25 on food and paid $4.00 for each ride. What was the greatest number

Shtirlitz [24]

Answer is 4 rides
19.75 after food so divide it by 4 to get your answer

8 0

2 years ago

The square of a number decreased by 3 times the number 28 find all possible values for the number

stealth61 [152]

Question:

The square of a number decreased by 3 times the number is 28 find all possible values for the number

Answer:

The possible values of number are 7 and -4

Solution:

Given that the square of a number decreased by 3 times the number is 28

To find: all possible values of number

Let "a" be the unknown number

From given information,

square of a number decreased by 3 times the number = 28

$a^2 - 3a = 28$

$a^2 - 3a - 28 = 0$

Let us solve the above quadratic equation

$\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0$

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Using the above formula,

$\text { For } a^{2}-3 a-28=0 \text { we have } a=1, b=-3, c=-28$

$\begin{aligned}&a=\frac{-(-3) \pm \sqrt{(-3)^{2}-4(1)(-28)}}{2 \times 1}\\\\&a=\frac{3 \pm \sqrt{9+112}}{2}\\\\&a=\frac{3 \pm \sqrt{121}}{2}=\frac{3 \pm 11}{2}\\\\&a=\frac{3+11}{2} \text { or } a=\frac{3-11}{2}\\\\&a=7 \text { or } a=-4\end{aligned}$

Thus the possible values of number are 7 and -4

5 0

2 years ago

If m∠1 = 50, then m∠5 =

yawa3891 [41]

1. angle 1 = 50 degrees [ Reason is Given]
2. angle 1 and angle 5 are corresponding angles [Given]
3..Therefore angle1=angle 5 [ Corresponding angles are =]
4..Therefore angle 5 = 50 degrees [= angles have same measure]

The above assumes that we are talking about corresponding angles of congruent or similar polygons or corresponding angles forme when a transversal intersects two parallel lines

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2 years ago

Mr.Walden wrote the expression. He asked his students to write an equivalent expression of simplified form.

mafiozo [28]

Answer:

option D

Brianna

Step-by-step explanation:

Given in the question the expression wrote by Mr.Walden

$\frac{p^{-5} }{q^{0} }$

To write the simplified form of this expression we will use negative rule of exponent

$b^{-n}$ = 1 / $b^{n}$

$q^{-5} = \frac{1}{q^{5} }$

so,

$\frac{1}{q^{5} x q^{0} }$

$\frac{1}{q^{5} p^{0} }$

Only Brianna wrote right simplification of the expression written by Mr.Walden

3 0

2 years ago

The points (–5, 6) and (5, 6) are vertices of a hexagon. The line segment joining the two points forms one of the sides of the h

xxTIMURxx [149]

The information about the points being vertices that make up a line to represent the side of a hexagon is irrelevant, as we are only looking for the distance of a line based on their x and y coordinates.

Look at the point's x and y coordinates:

First point:

x = -5, y = 6

Second point:

x = 5, y = 6

You'll notice that the y-coordinate for both points is the same (6 = 6). This means that the segment created by the points will be horizontal, since there is only movement on the x-axis if you trace the segment from point to point.

To find the distance between the two points, we'll only need to subtract the first point's x-coordinate from the second:

5 - (-5) = 5 + 5 = 10

The answer will be the following statement:

Since the y-coordinates are the same, the segment is horizontal, and the distance between the points is 10 units.

5 0

2 years ago

Read 2 more answers