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stiv31 [10]
2 years ago
4

Durante uma caminhada, estimei que o comprimento da sombra de um pequeno poste fosse seis vezes o comprimento da minha sombra. S

abendo que 1,70 m e considerando que a minha estimativa esteja correta, qual a altura do poste?
Mathematics
1 answer:
Sindrei [870]2 years ago
3 0

Answer:

hola

Step-by-step explanation:

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Consider a single spin of the spinner.
alex41 [277]

Answer:

"landing on a shaded portion and landing on a 3"

"landing on an unshaded portion and landing on a number less than 2 "

Step-by-step explanation:

Mutually exclusive means the events will have no intersection.

Let's look at your first choice:

"landing on a shaded portion and landing on an even number"

Landing on a shaded portion would be 1 or 4.

Landing on an even number would be 2 or 4.

There is an intersection (they contain a common element), the 4.

These events are not mutually exclusive.

Let's look at your second choice:

"landing on a shaded portion and landing on a number greater than 3"

Landing on a shaded portion would be 1 or 4.

Landing on a number greater than 3 would be just 4.

There is an intersection; they both contain 4.

These events are not mutually exclusive.

Let's look at your third choice:

"landing on a shaded portion and landing on a 3"

Landing on a shaded portion would be 1 or 4.

Landing on 3 would just be 3.

There is no common elements in the lists listed.  These events have no intersection.

These events are mutually exclusive.

Let's look at your fourth choice:

"landing on an unshaded portion and landing on an odd number"

Landing on a unshaded portion would be 2 or 3.

Landing on an odd number would be 1 or 3.

There is an intersection; they both have 3 in common.

These events are not mutually exclusive.

Let's look at your fifth choice:

"landing on an unshaded portion and landing on a number less than 2 "

Landing on an unshaded portion would 2 or 3.

Landing on a number less than 2 would be 1.

There is no intersection.

These events are mutually exclusive.

6 0
2 years ago
Read 2 more answers
You have decided to purchase a new Toyota 4Runner for $25,635. You have promised your daughter that the SUV will be hers when th
-Dominant- [34]

Ok so our two variables will be:

x=age y=price

Our equation is:

y= -3000x + $25,635


5 0
2 years ago
The keyless entry system in some cars uses a 4-digit keypad. There are 10 possible digits, and the digits can be repeated. How m
Len [333]
This item can be answered through the concept of fundamental principles of counting. In the first of the four digits, there are 10 possible digits. The same with all the other 3 places or digits of the code. That is,
                             n = 10 x 10 x 10 x 10 
Giving us the answer of 10,000. Thus, there are 10,000 possible keys for the keyless entry. 
8 0
2 years ago
Read 2 more answers
An anthropologist finds that a prehistoric bone contains less than 8.1% of the amount of Carbon-14 the bones would have containe
stealth61 [152]

Answer:

20,944 years

Step-by-step explanation:

The formula you use for this type of decay problem is the one that uses the decay constant as opposed to the half life in years.  We are given the k value of .00012.  If we don't know how much carbon was in the bones when the person was alive, it would be safer to say that when he was alive he had 100% of his carbon.  What's left then is 8.1%.  Because the 8.1% is left over from 100% after t years, we don't need to worry about converting that percent into a decimal.  We can use the 8.1.  Here's the formula:

N(t)=N_{0} e^{-kt}

where N(t) is the amount left over after the decay occurs, N_{0} is the initial amount, -k is the constant of decay (it's negative cuz decay is a taking away from as opposed to a giving to) and t is the time in years.  Filling in accordingly,

8.1=100e^{-.00012t}

Begin by dividing the 100 on both sides to get

.081=e^{-.00012t}

Now take the natural log of both sides.  Since the base of a natual log is e, natural logs and e "undo" each other, much like taking the square root of a squared number.

ln(.081)= -.00012t

Take the natual log of .081 on your calculator to get

-2.513306124 = -.00012t

Now divide both sides by -.00012 to get t = 20,944 years

4 0
2 years ago
Jeri finds a pile of money with at least $\$200$. If she puts $\$50$ of the pile in her left pocket, gives away $\frac23$ of the
Marizza181 [45]

Answer:

The possible values of the number of dollars in the original pile of money is ≥ $200 but < $350

Step-by-step explanation:

Here we have, pile of money ≥ $200

Amount in put the left pocket = $50

Fraction given away = 2/3 of rest of pile ≥ 2/3×150 ≥ $100

Amount put in right pocket = ≥ $150 - $100 ≥ $50

Total amount remaining with Jeri = $50 +≥ $50 ≥ $100

Also original pile - $200 < $100

Therefore where maximum amount given away to have more money = $200 we have

2/3× (original pile - 50) = $200

Maximum amount for original pile = $350

Therefore the possible values of the number of dollars in the original pile of money is ≥ $200 but < $350.

6 0
2 years ago
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