I believe this would take the form of an exponential
equation:
A = Ao (1 + r)^t
where A is final population, Ao is initial population, r
is rate of growth and t is time
A / Ao = (1 + r)^t
log A / Ao = t log (1 + r)
t = (log A / Ao) / log (1 + r)
t = [log (1000 / 550)] / log (1.075)
t = 8.27 years
SO the answer is B) about 9 years
Answer:
b. can be larger, smaller, or equal to the number of degrees of freedom for the denominator.
Step-by-step explanation:
The distribution of all possible values of the f statistic is called an F distribution with various degree of freedom. For an F distribution, the F statistic is greater than or equal to zero and as the degrees of freedom for the numerator and for the denominator get larger, the curve approximates the normal.
For an F distribution, the number of degrees of freedom for the numerator can be larger, smaller, or equal to the number of degrees of freedom for the denominator.
Answer:


Step-by-step explanation:
The question is 
<em>We let
, so the equation becomes:</em>

Where 
Putting it in the quadratic formula, we have:
<u>Quadratic formula:</u> 
Substituting we have: 
<em>We let
, so x is:</em>
<em>
</em>
<em>and</em>
<em>
</em>
The solutions of the equation is
(rounded to 2 decimal places), and
(rounded to 2 decimal places)
Answer:
Step-by-step explanation:
Hello!
Given the linear regression of Y: "Annual salary" as a function of X: "Mean score on teaching evaluation" of a population of university professors. It is desired to study whether student evaluations are related to salaries.
The population equation line is
E(Y)= β₀ + β₁X
Using the information of a n= 100 sample, the following data was calculated:
R²= 0.23
Coefficient Standard Error
Intercept 25675.5 11393
x 5321 2119
The estimated equation is
^Y= 25675.5 + 5321X
Now if the interest is to test if the teaching evaluation affects the proffesor's annual salary, the hypotheses are:
H₀: β = 0
H₁: β ≠ 0
There are two statistic you can use to make this test, a Student's t or an ANOVA F.
Since you have information about the estimation of β you can calculate the two tailed t test using the formula:
~
= 25.1109
The p-value is two-tailed, and is the probability of getting a value as extreme as the calculated
under the distribution 
p-value < 0.00001
I hope it helps!
Answer:
20.39
Step-by-step explanation:
35.99 – 15.6 = 20.39