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lozanna [386]
2 years ago
15

Find out three rational numbers lying between 2/3 and 3/4

Mathematics
2 answers:
Karo-lina-s [1.5K]2 years ago
7 0

Answer:

33/48, 34/48, 35/48

Step-by-step explanation:

2/3 is equal to 32/48 and 3/4 is equal to 36/48. The fractions in between them are all rational numbers. Hope this helped <3

andrey2020 [161]2 years ago
7 0
2/3 = 2000/3000
3/4 = 2250/3000

Here are 248 rational numbers between them:
2001/3000
2002/3000
2003/3000
2004/3000
2005/3000
2006/3000
2007/3000
2008/3000
2009/3000
2010/3000
2011/3000
2012/3000
2013/3000
2014/3000
2015/3000
2016/3000
2017/3000
2018/3000
2019/3000
2020/3000
2021/3000
2022/3000
2023/3000
2024/3000
2025/3000
2026/3000
2027/3000
2028/3000
2029/3000
2030/3000
2031/3000
2032/3000
2033/3000
2034/3000
2035/3000
2036/3000
2037/3000
2038/3000
2039/3000
2040/3000
2041/3000
2042/3000
2043/3000
2044/3000
2045/3000
2046/3000
2047/3000
2048/3000
2049/3000
2050/3000
2051/3000
2052/3000
2053/3000
2054/3000
2055/3000
2056/3000
2057/3000
2058/3000
2059/3000
2060/3000
2061/3000
2062/3000
2063/3000
2064/3000
2065/3000
2066/3000
2067/3000
2068/3000
2069/3000
2070/3000
2071/3000
2072/3000
2073/3000
2074/3000
2075/3000
2076/3000
2077/3000
2078/3000
2079/3000
2080/3000
2081/3000
2082/3000
2083/3000
2084/3000
2085/3000
2086/3000
2087/3000
2088/3000
2089/3000
2090/3000
2091/3000
2092/3000
2093/3000
2094/3000
2095/3000
2096/3000
2097/3000
2098/3000
2099/3000
2100/3000
2101/3000
2102/3000
2103/3000
2104/3000
2105/3000
2106/3000
2107/3000
2108/3000
2109/3000
2110/3000
2111/3000
2112/3000
2113/3000
2114/3000
2115/3000
2116/3000
2117/3000
2118/3000
2119/3000
2120/3000
2121/3000
2122/3000
2123/3000
2124/3000
2125/3000
2126/3000
2127/3000
2128/3000
2129/3000
2130/3000
2131/3000
2132/3000
2133/3000
2134/3000
2135/3000
2136/3000
2137/3000
2138/3000
2139/3000
2140/3000
2141/3000
2142/3000
2143/3000
2144/3000
2145/3000
2146/3000
2147/3000
2148/3000
2149/3000
2150/3000
2151/3000
2152/3000
2153/3000
2154/3000
2155/3000
2156/3000
2157/3000
2158/3000
2159/3000
2160/3000
2161/3000
2162/3000
2163/3000
2164/3000
2165/3000
2166/3000
2167/3000
2168/3000
2169/3000
2170/3000
2171/3000
2172/3000
2173/3000
2174/3000
2175/3000
2176/3000
2177/3000
2178/3000
2179/3000
2180/3000
2181/3000
2182/3000
2183/3000
2184/3000
2185/3000
2186/3000
2187/3000
2188/3000
2189/3000
2190/3000
2191/3000
2192/3000
2193/3000
2194/3000
2195/3000
2196/3000
2197/3000
2198/3000
2199/3000
2200/3000
2201/3000
2202/3000
2203/3000
2204/3000
2205/3000
2206/3000
2207/3000
2208/3000
2209/3000
2210/3000
2211/3000
2212/3000
2213/3000
2214/3000
2215/3000
2216/3000
2217/3000
2218/3000
2219/3000
2220/3000
2221/3000
2222/3000
2223/3000
2224/3000
2225/3000
2226/3000
2227/3000
2228/3000
2229/3000
2230/3000
2231/3000
2232/3000
2233/3000
2234/3000
2235/3000
2236/3000
2237/3000
2238/3000
2239/3000
2240/3000
2241/3000
2242/3000
2243/3000
2244/3000
2245/3000
2246/3000
2247/3000
2248/3000
2249/3000
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The ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

Step-by-step explanation:

Let's call:

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S=a*h (equation 1)

but we can divide the triangle in two right triangles using the height line. So the total area will be equal to the addition of each individual area.

S=S_1+S_2 (equation 2)

S_1=a_1*h

But we can write S_1 in terms of \alpha _1, like this:

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S_2=\frac{h^{2} }{\tan(\alpha _2)}

Replacing in the equation 2:

S=\frac{h^{2} }{\tan(\alpha _1)}+\frac{h^{2} }{\tan(\alpha _2)}\\S=h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})

And replacing in the equation 1:

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So, we can replace all the known data in the last equation:

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