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Darina [25.2K]
2 years ago
14

What is the volume of a hemisphere with a diameter of 54.8 in, rounded to the nearest tenth of a cubic inch?

Mathematics
2 answers:
suter [353]2 years ago
7 0

Answer:

The volume of the hemisphere is 43083 in³

Step-by-step explanation:

The hemisphere is half a sphere, in order to calculate it's volume we need to calculate the volume of a sphere with the same radius and divide it by 2. We have:

Volume = [(4/3)*pi*r³]/2

Where r = d/2 = 54.8/2 = 27.4 in. Applying this to the equation we have:

Volume = [(4/3)*pi*(27.4)³]/2 = 43083 in³

The volume of the hemisphere is 43083 in³

alexandr402 [8]2 years ago
3 0

Answer:

Step-by-step explanation:

43083.4 in

3

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A certain car traveling at 34.0 mph skids to a stop in 29 meters from the point where the brakes were applied. in approximately
Orlov [11]
<span>Using the kinematic equations: (final velocity)^2 = (initial velocity)^2 - 2 * acceleration * distance Assuming the acceleration/deceleration on the car is constant from a constant force on the brakes. Converting from mph to m/s using 0.447 (so 34 mph is 15.2 m/s) (0)^2 = (15.2)^2 - 2 * acceleration * 29 acceleration = 4.0 m/s^2 Had the car been going 105.4 mph (47.1 m/s) (0)^2 = (47.1)^2 - 2 * 4 * distance distance = 277 meters</span>
6 0
2 years ago
the means of a proportion are 21 and 33. List all possible pairs of positive integers that could be the extremes of the true pro
prisoha [69]
X/21 = y/33

xy = 21·33 = 693

The factors of 693 are 1,3,7,9,11,21,33,63,77,99,231,693.

(x,y) = (1,693), (693,1), (3,231), (231,3), (7,99), (99,7), (9,77), (77,9), (11,63), (63,11), (21,33), (33,21)
7 0
2 years ago
Jenna's heart rate is 60 beats per minute. If Jenna's heart beat 747,533 times, how much time has elapsed? Give your answer in d
olganol [36]

Answer:

Days- 9

Hours- 208

Minutes- 12,459

Step-by-step explanation:

For minutes,

747,533 ÷ 60 = 12,458.883 ≈ 12,459 minutes

For hours,

60 minutes to pass an hour so, 60 × 60 = 3600 minutes

747,533 ÷ 3600 = 207.648 ≈ 208 hours

For days,

1 day = 24 hours

1 hour = 3600 beats

24 × 3600 = 86400

747,533 ÷ 86400 = 8.652 ≈ 9 days

4 0
2 years ago
Read 2 more answers
Consider this system of inequalities. x + y ≤ –3 y &lt; StartFraction x Over 2 EndFraction Which graph shows the solution for th
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Answer:

the answer is c

Step-by-step explanation:

i just did it

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2 years ago
The heights of a random sample of 50 college students showed a mean of 174.5 centimeters and a standard deviation of 6.9 centime
Minchanka [31]

Answer:

Step-by-step explanation:

Hello!

For me, the first step to any statistics exercise is to determine what is the variable of interest and it's distribution.

In this example the variable is:

X: height of a college student. (cm)

There is no information about the variable distribution. To estimate the population mean you need a variable with at least a normal distribution since the mean is a parameter of it.

The option you have is to apply the Central Limit Theorem.

The central limit theorem states that if you have a population with probability function f(X;μ,δ²) from which a random sample of size n is selected. Then the distribution of the sample mean tends to the normal distribution with mean μ and variance δ²/n when the sample size tends to infinity.

As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.

The sample size in this exercise is n=50 so we can apply the theorem and approximate the distribution of the sample mean to normal:

X[bar]~~N(μ;σ2/n)

Thanks to this approximation you can use an approximation of the standard normal to calculate the confidence interval:

98% CI

1 - α: 0.98

⇒α: 0.02

α/2: 0.01

Z_{1-\alpha /2}= Z_{1-0.01}= Z_{0.99} =2.334

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

174.5 ± 2.334* \frac{6.9}{\sqrt{50} }

[172.22; 176.78]

With a confidence level of 98%, you'd expect that the true average height of college students will be contained in the interval [172.22; 176.78].

I hope it helps!

4 0
2 years ago
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