Answer:
Following are the code to this question:
CarCounter::~CarCounter()//Defining destructor CarCounter
{
cout << "Destroying CarCounter\n";//print message Destroying CarCounter
}
Explanation:
Following are the full program to this question:
#include <iostream>//Defining header file
using namespace std;
class CarCounter //Defining class CarCounter
{
public:
CarCounter();//Defining constructor CarCounter
~CarCounter();//Defining destructor CarCounter
private:
int carCount;//Defining integer variable carCount
};
CarCounter::CarCounter()//declaring constructor
{
carCount = 0;//assign value in carCount variable
return;//using return keyword
}
CarCounter::~CarCounter()//Defining destructor CarCounter
{
cout << "Destroying CarCounter\n";//print message Destroying CarCounter
}
int main() //Defining main method
{
CarCounter* parkingLot = new CarCounter();//Defining class object parkingLot
delete parkingLot;//
return 0;
}
- In the given C++ language code, a class "CarCounter" is defined, and inside the class, a "constructor, Destructors, and an integer variable" is defined.
- Outside the class, the scope resolution operator is used to define the constructor and assign value "0" in the integer variable.
- In the above-given code, the scope resolution operator, to define destructor and inside this cout function is used, which prints a message.
- In the main method, the class object is created, which automatically calls its class constructor and destructors.
The argument for the function would be answer "D".
Return them they are probably defective or turn ur media volume all the way down.
Answer:
// A optimized school method based C++ program to check
// if a number is composite.
#include <bits/stdc++.h>
using namespace std;
bool isComposite(int n)
{
// Corner cases
if (n <= 1) return false;
if (n <= 3) return false;
// This is checked so that we can skip
// middle five numbers in below loop
if (n%2 == 0 || n%3 == 0) return true;
for (int i=5; i*i<=n; i=i+6)
if (n%i == 0 || n%(i+2) == 0)
return true;
return false;
}
// Driver Program to test above function
int main()
{
isComposite(11)? cout << " true\n": cout << " false\n";
isComposite(15)? cout << " true\n": cout << " false\n";
return 0;
}
Explanation:
Answer:
nothing
Explanation:
Because the return type of the function is void. void means does not return any thing.
The syntax of the function:
type name( argument_1, argument_2,......)
{
statement;
}
in the declaration the type define the return type of the function.
it can be int, float, double, char, void etc.
For example:
int count( int index);
the return type of above function is int. So, it return integer.
similarly,
void count(int index);
it return type is void. So, it does not return any thing.