The rubber track for a toy digger goes around four circular wheels of diameter 8 cm, as shown. (b) Calculate the length of the r
ubber track that goes around the four wheels. Give your answer correct to one decimal place.
2 answers:
This question is incomplete because it lacks the diagram of the 4 circular wheels.
Find attached to this answer the appropriate diagram
Answer:
100.5cm
Step-by-step explanation:
The formula to be used in this calculation is the circumference of a circle.
The circumference of a circle can be defined as the actual length of a circle when it is stretch out(opened up) or the distance around a circle.
The formula for the circumference of a circle is given as 2πr where r = radius of the circle
Or πD where D = Diameter of the circle
In the question, we are given the diameter of the circle = 8cm
So we use the Formula
= πD
The length of the rubber track around one wheel is
= π × 8cm = 25.132741229cm
From the attached diagram, we can see we have 4 wheels.
The length of the rubber track that goes around the four wheels is calculated as
4 × 25.132741229cm = 100.53096491cm.
Approximately to one decimal place = 100.5cm
Therefore, the length of the rubber track that goes around the four wheels to one decimal place is 100.5cm
Answer:
73.1 cm
Step-by-step explanation:
In the drawing, the rubber track is in black and the wheels are in light gray.
As we can see in the figure, the rubber track will have a length of two halfs of a circunference of radius 8 cm plus six diameters of 8 cm. So the total length is:
Length of rubber track = pi * 8 + 6 * 8 = 25.13 + 48 = 73.133 cm
Rounding to one decimal place, we have that the length is 73.1 cm
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Answer:
27
Step-by-step explanation:
Given the expression
According to law of indices, this can be written as;
Hence the required answer is 27
Expected Mean, E(X), is obtained by multiplying each pair of 
and its 
and add up the answers
E(X) = (0×0.7) + (1×0.2) + (2×0.1) = 0.4
The formula to calculate the variance, Var(X), is given by E(X)² - (E(X))²
E(X²) = (0²×0.7) + (1²×0.2) + (2²×0.1) = 0+0.2+0.4 = 0.6
(E(X))² = (0.4)² = 0.16
Var(X) = 0.6 - 0.16 = 0.44
Translating these answers into the context we have
E(Y) = 0.4×500 = $200
Var(Y) = $110
E(X) = (0×0.7) + (1×0.2) + (2×0.1) = 0.4
The formula to calculate the variance, Var(X), is given by E(X)² - (E(X))²
E(X²) = (0²×0.7) + (1²×0.2) + (2²×0.1) = 0+0.2+0.4 = 0.6
(E(X))² = (0.4)² = 0.16
Var(X) = 0.6 - 0.16 = 0.44
Translating these answers into the context we have
E(Y) = 0.4×500 = $200
Var(Y) = $110