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IRINA_888 [86]
2 years ago
10

The rubber track for a toy digger goes around four circular wheels of diameter 8 cm, as shown. (b) Calculate the length of the r

ubber track that goes around the four wheels. Give your answer correct to one decimal place.

Mathematics
2 answers:
Allushta [10]2 years ago
7 0

This question is incomplete because it lacks the diagram of the 4 circular wheels.

Find attached to this answer the appropriate diagram

Answer:

100.5cm

Step-by-step explanation:

The formula to be used in this calculation is the circumference of a circle.

The circumference of a circle can be defined as the actual length of a circle when it is stretch out(opened up) or the distance around a circle.

The formula for the circumference of a circle is given as 2πr where r = radius of the circle

Or πD where D = Diameter of the circle

In the question, we are given the diameter of the circle = 8cm

So we use the Formula

= πD

The length of the rubber track around one wheel is

= π × 8cm = 25.132741229cm

From the attached diagram, we can see we have 4 wheels.

The length of the rubber track that goes around the four wheels is calculated as

4 × 25.132741229cm = 100.53096491cm.

Approximately to one decimal place = 100.5cm

Therefore, the length of the rubber track that goes around the four wheels to one decimal place is 100.5cm

Alika [10]2 years ago
5 0

Answer:

73.1 cm

Step-by-step explanation:

In the drawing, the rubber track is in black and the wheels are in light gray.

As we can see in the figure, the rubber track will have a length of two halfs of a circunference of radius 8 cm plus six diameters of 8 cm. So the total length is:

Length of rubber track = pi * 8 + 6 * 8 = 25.13 + 48 = 73.133 cm

Rounding to one decimal place, we have that the length is 73.1 cm

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2 years ago
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The roof of a house seen from the front is an isosceles triangle \Delta ABC ΔABC with base 14.5 m and sides of length 8.5 m. Fin
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Answer:

4.4 m

Step-by-step explanation:

Draw the height of the triangle (perpendicular line from point A to line BC).  Since ABC is an isosceles triangle, the height is a perpendicular bisector, so it splits the triangle into two congruent right triangles.

Use Pythagorean theorem to find the height.

c² = a² + b²

(8.5 m)² = (14.5/2 m)² + h²

h ≈ 4.4 m

7 0
2 years ago
Which properties are present in a table that represents an exponential function in the form y-b* when b > 1?
Oksana_A [137]

Answer:

<u>Properties that are present are </u>

Property I

Property IV

Step-by-step explanation:

The function given is  y=b^x  where b > 1

Let's take a function, for example,  y=2^x

Let's check the conditions:

I. As the x-values increase, the y-values increase.

Let's put some values:

y = 2 ^ 1

y = 2

and

y = 2 ^ 2

y = 4

So this is TRUE.

II. The point (1,0) exists in the table.

Let's put 1 into x and see if it gives us 0

y = 2 ^ 1

y = 2

So this is FALSE.

III. As the x-value increase, the y-value decrease.

We have already seen that as x increase, y also increase in part I.

So this is FALSE.

IV. as the x value decrease the y values decrease approaching a singular value.

THe exponential function of this form NEVER goes to 0 and is NEVER negative. So as x decreases, y also decrease and approached a value (that is 0) but never becomes 0.

This is TRUE.

Option I and Option IV are true.

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2 years ago
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Anne has 24 more cards than Devi.  Anne finds that 3/5 of Devi's cards are equal to 1/2 of her cards.  How many cards does Anne
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A=24xD
3/5xD=1/2xA
3d/5=12
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8 0
2 years ago
In circle N, KL ≅ ML. Circle N is shown. Line segments N J, N M, N L, and N K are radii. Lines are drawn to connect each point o
Sergeu [11.5K]

Answer:

arc\ JM=132^o

Step-by-step explanation:

The picture of the question in the attached figure

step 1

we know that

arc\ JM+arc\ ML+arc\ LK+arc\ KJ=360^o ----> by complete circle

substitute the given values

(13x+2)^o+(8x-3)^o+(7x+7)^o+(5x+24)^o=360^o

solve for x

(33x+30)^o=360^o\\33x=360-30\\33x=330\\x=10

step 2

Find the measure of arc JM

arc\ JM=(13x+2)^o

substitute the value of x

arc\ JM=(13(10)+2)^o=132^o

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