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Elodia [21]
2 years ago
14

Hugo is a veterinarian. He knows the following information about his 41 patrons: 20 patrons in total do not have a dog. 17 patro

ns in total have a cat. 7 patrons have neither a dog nor a cat. Can you help Hugo organize the results into a two-way frequency table? Have a cat, Have a dog
Have a cat, do not have a dog
Do not have a cat, Have a dog
Do not have a dog , Do not have a Cat
Mathematics
1 answer:
shtirl [24]2 years ago
4 0

Answer:

                            have dog          Not have dog    Total

have cat                     4                     13                   17

not have cat              17                    7                     24

Total                         21                    20                   41

Step-by-step explanation:

Total Patrons = 41

20 patrons in total do not have a dog

7 patrons have neither a dog nor a cat.

17 patrons in total have a cat.

                            have dog          Not have dog      Total

have cat                                                                      17

not have cat                                               7               24

Total                                                          20             41

Total patrons = 41

Total patrons not have dog = 20

So, Total patrons have dog = 41-20=21

Total patrons not have dog = 20

Patrons have neither a dog nor a cat =7

Patrons have cat but not dog = 20-7 = 13

Total patrons not having cat = 24

Patrons not having cat and not having dog = 7

So, patrons having dog but not having cat =24-7=17

Total patrons have cat = 17

patrons have cat but not dog = 13

So, patrons have cat and dog also = 17-13 =4

So, the required Two way table :

                            have dog          Not have dog    Total

have cat                     4                     13                   17

not have cat              17                    7                     24

Total                         21                    20                   41

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