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2 years ago

Jason worked the following hours in a month of June. What was the percentage increase from week 1 to week 3

Mathematics

1 answer:

olga55 [171]2 years ago

5 0

Answer:

133 1/3%

Step-by-step explanation:

From week 1 to week 3, it increased 6.

6 / 18 = 1 / 3

So it increased 133.33333333...%

You can simplify it to 133 1/3%

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On monday maggie ran n miles on tuesday she ran 90% of the number of miles she ran on monday and on tuesday she ran 50% of the n

kari74 [83]

Answer:

let number of mile on monday be x

tuesday = 9/10 of x

wednesday = 9/20 of x

Step-by-step explanation:

tues = 90/100=9/10

wednes = 50/100 * 90/100 * x

wednes = 9/20 of x

3 0

2 years ago

Exhibit 11-2 We are interested in determining whether the variances of the sales at two music stores (A and B) are equal. A samp

Fiesta28 [93]

Answer:

Option A , should not be rejected

Step-by-step explanation:

From the question we are told that:

Sample 1 $n=25$

Standard deviation 1 $\sigma_1=30$

Sample 2 $n=16$

Standard deviation 2 $\sigma_2=20$

Level of confidence $\alpha=95\%=>0.95$

Generally The Hypothesis are given as

$H_0:\sigma_1^2=\sigma_1^2$

$H_1:\sigma_1^2\neq \sigma_1^2$

Generally the equation for test Statistics is mathematically given by

$T=\frac{\sigma_1^2}{\sigma_2^2}$

$T=\frac{30^2}{20^2}$

$T=2.25$

Therefore

Critical Value

$X=(\alpha,df_1)$

$X'=(\alpha,df_2)$

Where

$df=n-1$

Therefore

$X=(0.95,24)$

$X'=(0.95,15)$

From Table

$T_{Critical}=T_x,T_{x'}$

$T_{Critical}=0.41,2.701$

Therefore

$T_x$

Hence,We fail to reject the Null Hypothesis $H_0$

Option A , should not be rejected

3 0

1 year ago

In parallelogram ABCD , diagonals AC⎯⎯⎯⎯⎯ and BD⎯⎯⎯⎯⎯ intersect at point E, AE=x2−16 , and CE=6x .

MAXImum [283]

Answer:

<h3>AC=96 units.</h3>

Step-by-step explanation:

We are given a parallelogram ABCD with diagonals AC and BD intersect at point E.

$AE=x^2-16.$ , and CE=6x .

<em>Note: The diagonals of a parallelogram intersects at mid-point.</em>

Therefore, AE = EC.

Plugging expressions for AE and EC, we get

$x^2-16=6x.$

Subtracting 6x from both sides, we get

$x^2-16-6x=6x-6x$

$x^2-6x-16=0$

Factoriong quadratic by product sum rule.

We need to find the factors of -16 that add upto -6.

-16 has factors -8 and +2 that add upto -6.

Therefore, factor of $x^2-6x-16=0$ quadratic is (x-8)(x+2)=0

Setting each factor equal to 0 and solve for x.

x-8=0 => x=8

x+2=0 => x=-2.

We can't take x=-2 as it's a negative number.

Therefore, plugging x=8 in EC =6x, we get

EC = 6(8) = 48.

<h3>AC = AE + EC = 48+48 =96 units.</h3>

5 0

2 years ago

A cooking magazine shows a photo of a main dish on the front cover of 5 out of the 12 issues it publishes each year. Write and s

Shtirlitz [24]

Ok so the ratio is ... 5/12 (every 5 months out of 12 in on year, the main dish is on the cover)

All you have to do is multiply the top # and bottom # in the fraction by 5.

5*5 = 25
5*12 = 60

In 5 years, there are 60 months. During that time, a main dish will be on the cover 25 times.

5 0

2 years ago

My cupcake recipe makes $12$ cupcakes and requires $1\frac12$ sticks of butter. I can only buy whole sticks of butter. How many

andre [41]

Answer:

Given that,

My cupcake recipe makes $12$ cupcakes and requires $1\frac12$ sticks of butter. I can only buy whole sticks of butter.

Therefore, 1 whole sticks of butter is enough to make $100$ cupcakes.

8 0

2 years ago

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