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krek1111 [17]
2 years ago
8

What is the following quotient? StartFraction StartRoot 6 EndRoot + StartRoot 11 EndRoot Over StartRoot 5 EndRoot + StartRoot 3

EndRoot EndFraction StartFraction StartRoot 30 EndRoot + 3 StartRoot 2 EndRoot + StartRoot 55 EndRoot + StartRoot 33 EndRoot Over 8 EndFraction StartFraction StartRoot 30 EndRoot minus 3 StartRoot 2 EndRoot + StartRoot 55 EndRoot minus StartRoot 33 EndRoot Over 2 EndFraction Seventeen-eighths Negative five-halves
Mathematics
2 answers:
Katen [24]2 years ago
6 0

Answer:

Option C on Edge2020.

Step-by-step explanation:

Delicious77 [7]2 years ago
5 0

Answer:

<h3>StartFraction StartRoot 30 EndRoot minus 3 StartRoot 2 EndRoot + StartRoot 55 EndRoot minus StartRoot 33 EndRoot Over 2</h3>

Step-by-step explanation:

Given the surdic equation as shown \frac{\sqrt{6}+\sqrt{11}  }{\sqrt{5}+\sqrt{3} }\\

To find the quotient, we will rationalize by multipying both numerator and denominator of the function by the conjugate of the denominator.

Given the denominator \sqrt{5}+\sqrt{3}, its conjugate will be \sqrt{5}-\sqrt{3}

Multiplying through by \sqrt{5}-\sqrt{3}, we have;

= \frac{\sqrt{6}+\sqrt{11}  }{\sqrt{5}+\sqrt{3} } * \frac{\sqrt{5}-\sqrt{3}  }{\sqrt{5}-\sqrt{3} }\\

= \frac{\sqrt{30}- \sqrt{18}+\sqrt{55}-\sqrt{33}}{2}\\= \frac{\sqrt{30}- \sqrt{9*2}+\sqrt{55}-\sqrt{33}}{2}\\= \frac{\sqrt{30}- 3\sqrt{2}+\sqrt{55}-\sqrt{33}}{2}

The final expression gives the requires answer

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Ivan used coordinate geometry to prove that quadrilateral EFGH is a square.
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Answer:

this is geometry?

Step-by-step explanation:

5 0
2 years ago
The star aldebaran, visible from earth, lies about 65 light years away from us. What is the minimum amount of time that would be
makkiz [27]
A beam of light (travelling at the speed of light) would take 65 years to go and 65 years to come back from aldebaran, i.e. 130 years. You can send and receive a radio message (travelling at the speed of light, being electromagnetic radiation) taking so 130 years.
8 0
2 years ago
Nathan is out rafting. He rafts 16 miles with the river current. At the end of 16 miles, he turns around and rafts the same dist
Novosadov [1.4K]
S = d/t

st = d

t = d/s

The time going is t1.
The time returning is t2.
The total time is 4 hours, so we have t1 + t2 = 4

The speed of the current is c.
The speed going is 9 + c.
The speed returning is 9 - c.

t1 = 16/(9 + c)

t2 = 16/(9 - c)

t1 + t2 = 16/(9 + c) + 16/(9 - c)

4 = 16/(9 - c) + 16/(9 + c)

1 = 4/(9 - c) + 4/(9 + c)

(9 + c)(9 - c) = 4(9 - c) + 4(9 + c)

81 - c^2 = 36 - 4c + 36 + 4c

81 - c^2 = 72

c^2 = 9

c^2 - 9 = 0

(c + 3)(c - 3) = 0

c + 3 = 0   or   c - 3 = 0

c = -3   or   c = 3

We discard the negative answer, and we get c = 3.

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7 0
2 years ago
Read 2 more answers
On Friday there were 8 snowboarders for every 3 skiers at Slovak ski resort. On Saturday the ratio of the number of snowboarders
atroni [7]

Answer:

There are 46 more skiers than snowboarder

Step-by-step explanation:

Given

Ratio of Snowboarders to Skiers

On Friday:

Ratio = 8 : 3

On Saturday:

Ratio = 4 : 7

Population = 168

Required

Determine the difference in the number of skiers and snowboarders on Saturday

On Saturday, we have

Ratio = 4 : 7

Calculate Total

Total = 4 + 7

Total = 11

Calculate the number of skiers

Skiers = \frac{7}{11} * 168

Skiers = \frac{1176}{11}

Skiers = 107 (Approximated)

Calculate the number of snowboarders

Snowboarders = \frac{4}{11} * 168

Snowboarders = \frac{672}{11}

Snowboarders = 61 (Approximated)

Calculate the difference

Difference = 107 - 61

Difference = 46

<em>Hence, there are 46 more skiers than snowboarder</em>

6 0
2 years ago
A bird travels 71.2 kilometers after 2 hours of flying. Complete the equation to represent the number of hours, t, the bird will
hoa [83]

Answer:

35.6t = d

Step-by-step explanation:

71.2 hours every 2 hours

Divide by 2 hours to find how far the bird travels in a single hour:

71.2 / 2 = 35.6

The bird travels 35.6 km every hour.

So given a number d, t is 35.6 times that number.

35.6t = d

3 0
2 years ago
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