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mart [117]
2 years ago
13

Which expressions are equivalent to StartFraction 1 Over 81 EndFraction? Check all that apply.

Mathematics
1 answer:
Anastaziya [24]2 years ago
7 0

The options are

(A)8^{-1} (B)9^{-2} (C)\dfrac{9^8}{9^4}  (D)\frac{9^8}{9^{10}}  (E)9^{-6}\cdot 9^3 (F)9^5 \cdot 9^{-7

Answer:

(B)9^{-2} \\ (D)\frac{9^8}{9^{10}} \\ (F)9^5 \cdot 9^{-7

Step-by-step explanation:

Given the fraction \dfrac{1}{81}

\dfrac{1}{81}=\dfrac{1}{9^2}=9^{-2

Any option that gives a form equivalent to any of the above is valid.

Option B= 9^{-2} which is equivalent

In Option D: \frac{9^8}{9^10}=9^{8-10}=9^{-2}

In Option F: 9^5 \cdot 9^{-7}=9^{5-7}=9^{-2}

Therefore, Options B, D and F are equivalent.

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A research organization keeps track of what citizens think is the most important problem facing the country today. They randomly
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Answer:

Step-by-step explanation:

From the information given, the population is divided into sub groups. Each group would consist of citizens picking a particular choice as the most important problem facing the country. The choices are the different categories. In this case, the null hypothesis would state that the distribution of proportions for all categories is the same in each population. The alternative hypothesis would state that the distributions is different. Therefore, the correct test to use to determine if the distribution of​ "problem facing this country ​today" is different between the two different​ years is

A) Use a​ chi-square test of homogeneity.

8 0
2 years ago
What are the domain and range of function p within the context of Melissa's garden?
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8 0
2 years ago
Elijah can spend up to $23 on groceries. She wants to buy 3 pounds of tomatoes, 4 pounds of oranges, and x pounds of lean ground
Colt1911 [192]

Answer: 2 pounds

Step-by-step explanation:

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7 0
2 years ago
It costs 20 cents to receive a photo and 30 cents to send a photo from a cellphone. C is the cost of one photo (either sent or r
ddd [48]

Answer:

(a) PC(C)=     \left \{ {{0.6 \ \ \ \ x=20} \atop 0.4 \ \ \ \ {x=30}} \right. \\\ 0 \ \ \ \ \ \ \ else

(b) E[C] = 24 cents

Step-by-step explanation:

Given:

Cost to receive a photo = 20 cents

Cost to send a photo = 30 cents

Probability of receiving a photo = 0.6

Probability of sending a photo = 0.4

We need to find

(a) PC(c)

(b) E[C]

Solution:

(a)

PC(C)=     \left \{ {{0.6 \ \ \ \ c=20} \atop 0.4 \ \ \ \ {c=30}} \right. \\\ 0 \ \ \ \ \ \ \ else

(b)

Expected value can be calculated by multiplying probability with cost.

E[C] = Probability × cost

E[C] = 0.6\times20 +0.4 \times 30 = 12 + 12 = 24\  cents

3 0
2 years ago
Evaluate 6+3b if b=7
Pavlova-9 [17]
27. Replace b with 7, making 6 + 3(7). The 3 and parentheses of 7 hint multiplication, so you multiply to make 21, then add 6 relating back to PEMDAS to teach you the correct order to solve the problem.
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2 years ago
Read 2 more answers
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