A sorveteria “Que calor” vendeu 70 picolés e faturou R$ 100,00.Que sistema de equações do 1º grau melhor traduz essa situação?

Find the midpoint of the segment between the points (3,17) and (−14,−8)

mixas84 [53]

Answer:

$\large\boxed{\left(-\dfrac{11}{2},\ \dfrac{9}{2}\right)}$

Step-by-step explanation:

The formula of a midpoint between two points A(x₁, y₁) and B(x₂, y₂):

$M_{AB}\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

We have the points (3, 17) and (-14, -8).

Substitute:

$M(x,\ y)\\\\x=\dfrac{3+(-14)}{2}=\dfrac{-11}{2}\\\\y=\dfrac{17+(-8)}{2}=\dfrac{9}{2}$

5 0

2 years ago

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Maria created a graph of B(t), the temperature over time. For the interval between t = 3 and t = 7, the average rate of change i

LuckyWell [14K]

What are the statements?

4 0

2 years ago

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Poor Milhouse is hopelessly in love with Lisa. Unfortunately for Milhouse, Lisa does not feel the same way. However, Milhouse re

rewona [7]

Answer:

15.6%

Step-by-step explanation:

Since each day there is a 6% chance that Lisa smiles at him then that means that each day there is a 94% chance that Lisa does not smile at him. To find the probability of Milhouse going longer than a month (30 days) without a smile from Lisa we need to multiply this percentage in decimal form for every day of the month. This can be solved easily by putting 94% to the 30th power which would be the same, but first, we need to turn it into a decimal...

94% / 100 = 0.94

$0.94^{30}$ = 0.156

Now we can turn this decimal into a percentage by multiplying by 100

0.156 * 100 = 15.6%

Finally, we can see that the probability that Milhouse goes longer than a month without a smile from Lisa is 15.6%

6 0

2 years ago

Rationalize the denominator of $\frac{2}{3\sqrt{5} + 2\sqrt{11}}$ and write your answer in the form $\displaystyle \frac{A\sqrt{

vlada-n [284]

Answer:

Step-by-step explanation:

Given the surdic expression $\frac{2}{3\sqrt{5} + 2\sqrt{11}}\\$ , to rationalize the expression, we will have to multiply the numerator and denominator of the expression by the conjugate of the denominator as shown;

$= \frac{2}{3\sqrt{5} + 2\sqrt{11}} * \frac{3\sqrt{5} - 2\sqrt{11}}{3\sqrt{5} - 2\sqrt{11}}\\\\= \frac{2(3\sqrt{5} - 2\sqrt{11})}{(3\sqrt{5} + 2\sqrt{11})(3\sqrt{5} - 2\sqrt{11})}\\\\= \frac{6\sqrt{5} - 4\sqrt{11} }{9\sqrt{25}+6\sqrt{55}- 6\sqrt{55}-4\sqrt{121} } \\\\= \frac{6\sqrt{5} - 4\sqrt{11} }{9(5)-4(11) }\\\\= \frac{6\sqrt{5} - 4\sqrt{11} }{45-44 }\\\\= \frac{6\sqrt{5} - 4\sqrt{11} }{1}$

Comparing the result $\frac{6\sqrt{5} - 4\sqrt{11} }{1}$ with the expression $\frac{A\sqrt{B} + C\sqrt{D}}{E}$ , it can be seen that A = 6, B = 5, C = -4, D = 11 and E = 1

A+B+C+D+E = 6+5+(-4)+11+1

A+B+C+D+E = 11-4+12

A+B+C+D+E = 19

Hence the value of A+B+C+D+E is 19

4 0

2 years ago

$abcd$ is a square. how many squares have two or more vertices in the set $\{a, b, c, d\}$?

marshall27 [118]

There are 4 squares having a side corresponding to a side of square abcd.

There are 4 squares having a side corresponding to the diagonals of square abcd.

And then the original square

Therefore, there are 4 + 4 + 1 = 9 squares <span>having two or more vertices in the set {a, b, c, d}.</span>

7 0

2 years ago

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