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ozzi
2 years ago
6

Un equipo de fútbol se conforma de cuatro líneas de jugadores: portero (9%), defensas (37%), medios (27%) y delanteros (27%), do

nde los goles anotados por el equipo en cada línea son: portero 1 gol, defensas 11 goles, medios 15 goles y delanteros 23. Supongamos que en un partido se gana por un gol. ¿Qué probabilidad hay de que este fuera anotado (a) por la defensa, (b) por los medios y (c) por los delanteros?
Mathematics
1 answer:
Tpy6a [65]2 years ago
3 0

Answer:

According to the proble, the total number of goals are 1+11+15+23 = 50: 1 by the goalkeeper, 11 by defense, 15 by midfielders and 23 by strikers.

So, each probability can be found by using standard probabilities

P=\frac{events}{total outcomes}

<h3>(a) Defense</h3>

P=\frac{11}{50} \approx 0.22

Therefore, the defense has a probability of 22% of score that goal.

<h3>(b) Midfielders</h3>

P=\frac{15}{50} \approx 0.30

Therefore, midfielders have a probability of 30% of scoring that goal.

<h3>(c) Strikers.</h3>

P=\frac{23}{50} \approx 0.46

Therefore, strikers have a probability of 46% of scoring that goal.

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Arada [10]

Answer:

The test contains 10 three-point questions and 14 five-point questions.

Step-by-step explanation:

The value of x is the number of 3-point questions, and the value of y is the number of 5-point questions, as the problem statement tells you. So, the solution (x, y) = (10, 14) indicates ...

"The test contains 10 three-point questions and 14 five-point questions."

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You can try the offered answers to see which might apply. The last choice has too many questions. The first and third choices don't add up to 100 points.

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2 years ago
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The following are the hypotheses for a test of the claim that college graduation statue and cola preference are independent. H0:
Shkiper50 [21]

Answer:

\chi^2 = 0.579

And the critical value for the significance level used is:

\chi^2_{crit}= 5.991

Since the calculated value is less than the critical value we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the College graduation status and cola preference are independent

Step-by-step explanation:

For this case we want to test the following hypothesis:

Null hypothesis: College graduation status and cola preference are independent

Alternative hypothesis: College graduation status and cola preference are dependent

For this case we got a calculated statistic of:

\chi^2 = 0.579

And the critical value for the significance level used is:

\chi^2_{crit}= 5.991

Since the calculated value is less than the critical value we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the College graduation status and cola preference are independent

7 0
2 years ago
The distance between New York and Philadelphia by railroad is 90 miles; the distance between them by river and ocean is 240 mile
VladimirAG [237]
Start with 90/240, then reduce the fraction
you can reduce by dividing each by 10 to get 9/24
reduce more from there, seeing that each number can be divided by 3
9/3  = 3
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2 years ago
The height of a baseball thrown from the catcher to first base is modeled by the function h(t) = –0.09t2 + 0.72t + 6, where h is
Black_prince [1.1K]

The height of a baseball thrown from the catcher to first base is modeled by the function h(t) = -0.09t^2 + 0.72t + 6, where h is the height of the ball measured in feet and t is the time since being thrown, measured in seconds

To find out height of the ball at 10 seconds, we plug in 10 for t

h(t) = -0.09t^2 + 0.72t + 6

h(10) = -0.09(10)^2 + 0.72(10) + 6

h(10)=4.2 feet

the height of the ball at 10 seconds= 4.2 feet

3 0
2 years ago
Clarissa needs a $2,500 loan in order to buy a car. Which loan option would allow her to pay the least amount of interest?
denis-greek [22]

Answer:

Option A.

Step-by-step explanation:

Clarissa needs a $2,500 loan in order to buy a car.

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\frac{P\times R\times time}{100}

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= $250

C) Principal 2,500 interest 4.25% and time 24 months (2 years)

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= $212.50

D) Principal 2,500 interest 4.50% and time 36 months (3 years)

\frac{2500\times 4.5\times 3}{100}

= $337.50

The least amount of interest would be in option A.

5 0
2 years ago
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