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Novay_Z [31]
2 years ago
6

The Hawkins Supply company is currently faced with an inventory rotation problem. This difficulty stems from the fact that some

supplies must be used prior to a stated expiration date. Upon receipt, a new shipment of these perishable items must be stacked beneath the boxes that are currently in inventory. A substantial amount of time is consumed in restacking the items according to their expiration dates.
Business
1 answer:
Serga [27]2 years ago
7 0

Here's the completed question.

Question: The company would like to reduce the double and sometimes triple handling of items. How can this goal be achieved? Are there alternative solutions which might also be effective?

Answer:

1. Using the Just in Time Management inventory technique.

2. Using automated inventory processing systems, changing physical layout of warehouse.

Explanation:

1. The Just in time method would allow Hawkins Supply company to quickly process its inventory by adopting a principle of processing smaller batches with reduced factory space. Doing so would minimise the worries about expired inventory since the inventory isn't excessive.

2. There are automated softwares such as the KANBAN system that would automated the process, requiring lesser use receipts to track inventories. Another alternative is to restructure the warehouse by making provision for racks that could be numbered serially to easily find desired inventory.

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When Coca-Cola determines the bottled-water competitors for its Dasani brand by identifying the products or sets of products wit
GarryVolchara [31]

Answer: Category membership

Explanation:    

 According to the given question, the given situation is basically determining the dasani's category membership as it helps in categorizing the various types of products and the services on the basis of their similar features and the characteristics.

The main purpose of the category membership is that it helps in understanding the various types of offers related to the specific brand and also the high competitive choice.

The customers basically wanted the product at lower price with high quality and they usually prefer the discount offers. Therefore, Category membership is the correct answer.  

   

4 0
2 years ago
Alice works for a large advertising agency where she is hoping to be promoted to a management position. alice's mother and two s
Daniel [21]
I would say this could be a kind of statute of limitations whereby the potential for illness would only figure into the decision in the case of Alice and her present and past medical condition and not extend to her family propensities.
4 0
1 year ago
An investor has purchased stock in a firm. The investor believes that, at the end of the year, there is 0.20 probability that th
disa [49]

Answer:

loss of $200

Explanation:

As given, there are three cases can happen:

1) 0.20 probability that the stock will show a $3000 profit

=> 0.20 probability that profit = $3,000

2) 0.10 probability that the stock will show a $6000 profit

=> 0.10 probability that profit = $6,000

3) 0.70 probability that the stock will show a $2000 loss

=> 0.70 probability that profit = - $2,000

The expected profit in the stock at the end of the year can be calculated as following:

<em>Expected profit = Probability case 1 x Profit case 1 + Probability case 2 x Profit case 2 + Probability case 3 x Profit case 3 </em>

<em>=0.2 x 3,000 + 0.1 x 6,000 + 0.7 x (-2,000)</em>

<em>=. 600 + 600 -1,400 = -200</em>

<em />

So that, the expected profit in the stock is the loss of $200

5 0
2 years ago
Show that if the contribution to profit for trains is between $1.50 and $3, the current basis remains optimal. If the contributi
Dmitriy789 [7]

Answer:

210

Explanation:

Let us consider that x is the number of soldiers produced each week and y is number of trains produced each week.

Also, weekly revenues and costs can be expressed in terms of the decision variables x and y.

Then,

Hence the profit which we want to maximize is given by,

Now the constraints are given as,

Finishing Constraint:

Each week, no more than 100 hours of finishing time may be used.

Carpentry Constraint:

Each week, no more than 80 hours of carpentry time may be used.

Demand Constraint:

Because of limited demand, at most 40 soldiers should be produced each week.

Combining the sign restrictions and with the objective function  and constraints,and yield the following optimization model:

Such that,

First convert the given inequalities into equalities:

From equation (1):

If x=0 in equation (1) then (0,100)

If y=0 in equation (1) then (50,0)

From equation (2):

If x=0 in equation (2) then (0,80)

If y=0 in equation (2) then (80,0)

From equation (3):

Equation (3) is the line passing through the point x=40.

Therefore, the given LPP has a feasible solution first image

The optimum solution for the given LPP is obtained as follows in the second image

The optimal solution to this problem is,

And the optimum values are  .

Let c be the contribution to profit by each train. We need to find the values of c for which the current, basis remain optimal. Currently c is 2, and each iso-profit line has the form

3x +  2y = constant

y = 3x/2 +constant/ 2

And so, each iso-profit line has a slope of  .

From the graph we can see that if a change in c causes the isoprofit lines to be flatter than the carpentry constraint, then the optimal solution will change from the current optimal solution to a new optimal solution, If the profit for each train is c, the slope of each isoprofit line will be.

-3/c

Because the slope of the carpentry constraint is –1, the isoprofit lines will be flatter than the carpentry constraint.

If,

-3/c<-1

c >3

and the current basis will no longer be optimal. The new optimal solution will be point A of the graph.

If the is oprofit lines are steeper than the finishing constraint, then the optimal solution will change from point B to point C. The slope of the finishing constraint is –2.

If,

-3/c < -2 or

C < 1.5

Then the current basis is no longer optimal and point C,(40,20), will be optimal. Hence when the contribution to the profit for trains is between $1.50 and $3, the current basis remains optimal.

Again, consider the contribution to the profit for trains is $2.50, then the decision variables remain the same since the contribution to the profit for trains is between $1.50 and $3. And the optimal solution is given by,

z = 3× (20) + 2.5 × (60)

= 60 + 150

= 210

5 0
2 years ago
Which currency is normally used for conducting global trade between two countries? currency of the seller
Kryger [21]

Often times the currency used is the currency of the seller.

7 0
2 years ago
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