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2 years ago

4

There are 4 blue tiles, 12 red tiles, and 6 green tiles in a bag. Which model represents the probability, P, that Luke will pick

a red tile from the bag?

1 answer:

Lorico [155]2 years ago

5 0

Answer:

<em>The Probability that will pick a red tile from the bag</em>

$P(E) = \frac{6}{11}$ = 0.545

Step-by-step explanation:

<u><em>Explanation</em></u>:-

<em>Given data 4 blue tiles, 12 red tiles, and 6 green tiles in a bag</em>

<em>Total = 4 B + 12 R + 6 G = 22 tiles</em>

Total number of exhaustive cases

n (S) = $22 C_{1} = 22 ways$

<em>The Probability that will pick a red tile from the bag</em>

<em></em> $P(E) = \frac{n(E)}{n(S)} = \frac{12 C_{1} }{22 C_{1} } = \frac{12}{22}$ <em></em>

$P(E) = \frac{6}{11}$

<em>P(E) = 0.545</em>

<u><em>Final answer</em></u><em>:-</em>

<em>The Probability that will pick a red tile from the bag = 0.545</em>

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Step-by-step explanation:

$12\frac{1}{3}b+6\frac{2}{3}-10\frac{2}{3}b$

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$1\frac{2}{3}b+6\frac{2}{3}$

Since you cannot do any more combination or simplification, you are done. Hope this helps!

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2 years ago

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2 years ago

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Fittoniya [83]

Answer:

12 minutes

Step-by-step explanation:

Candles can be manually packed at the rate of ...

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2 years ago

replace each star with a digit to make the problem true.Is there only one answer to each problem? ****-***=2

Semenov [28]

Answer: We have two solutions:

1000 - 998 = 2

1001 - 999 = 2

Step-by-step explanation:

So we have the problem:

****-*** = 2

where each star is a different digit, so in this case, we have a 4 digit number minus a 3 digit number, and the difference is 2.

we know that if we have a number like 99*, we can add a number between 1 and 9 and we will have a 4-digit as a result:

So we could write this as:

1000 - 998 = 2

now, if we add one to each number, the difference will be the same, and the number of digits in each number will remain equal:

1000 - 998 + 1 - 1 = 2

(1000 + 1) - (998 + 1) = 2

1001 - 999 = 2

now, there is a trivial case where we can find other solutions where the digits can be zero, like:

0004 - 0002 = 2

But this is trivial, so we can ignore this case.

Then we have two different solutions.

7 0

2 years ago

Milton spilled some ink on his homework paper. He can't read the coefficient of $x$, but he knows that the equation has two dist

Lera25 [3.4K]

Answer:

$Sum = -81$

Step-by-step explanation:

See the comment for complete question.

Given

$c = 36$ ----- Constant

No coefficient of x^2

Required:

Determine the sum of all distinct positive integers of the coefficient of x

Reading through the complete question, we can see that the question has 3 terms which are:

x^2 ---- with no coefficient

x ---- with an unknown coefficient

36 ---- constant

So, the equation can be represented as:

$x^2 + ax + 36 = 0$

Where a is the unknown coefficient

From the question, we understand that the equation has two negative integer solution. This can be represented as:

$x = -\alpha$ and $x = -\beta$

Using the above roots, the equation can be represented as:

$(x + \alpha)(x + \beta) = 0$

Open brackets

$x^2 + (\alpha + \beta)x + \alpha \beta = 0$

To compare the above equation to $x^2 + ax + 36 = 0$ , we have:

$a = \alpha + \beta$

$\alpha \beta = 36$

Where: $\alpha, \beta$ and $\alpha \ne \beta$

The values of $\alpha$ and $\beta$ that satisfy $\alpha \beta = 36$ are:

$\alpha = -1$ and $\beta = -36$

$\alpha = -2$ and $\beta = -18$

$\alpha = -3$ and $\beta = -12$

$\alpha = -4$ and $\beta = -9$

So, the possible values of a are:

$a = \alpha + \beta$

When $\alpha = -1$ and $\beta = -36$

$a = -1 - 36 = -37$

When $\alpha = -2$ and $\beta = -18$

$a = -2 - 18 = -20$

When $\alpha = -3$ and $\beta = -12$

$a = -3 - 12 = -15$

When $\alpha = -4$ and $\beta = -9$

$a = -4 - 9 = -13$

At this point, we have established that the possible values of a are: -37, -20, -15 and -9.

The required sum is:

$Sum = -37 -20 -15 - 9$

$Sum = -81$

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2 years ago