Question

Which graph represents an odd function? On a coordinate plane, a function has two curves. The first curve is in quadrants 2 and 3 and has a minimum value of (negative 1, negative 3). The curve intersects the x-axis at (negative 2, 0) and goes to (0, 0). The second curve is in quadrants 1 and 4 and has a minimum value of (1, negative 3). The curve starts at (0, 0) and intercepts the x-axis at (2, 0). On a coordinate plane, a curved line crosses the x-axis at (negative 4, 0), (0, 0), and (4, 0). On a coordinate plane, a v-shaped function opens up. The function goes through (0, 2), has a vertex at (2, 0), and goes through (5, 3). On a coordinate plane, a curve has a maximum point at (0.5, 1) and a minimum point at (2, 0). The curve goes through points (0, 0) and (3, 4).

Answer 1

Answer:

  On a coordinate plane, a curved line crosses the x-axis at (negative 4, 0), (0, 0), and (4, 0)

Step-by-step explanation:

An odd function is symmetrical about the origin. It will satisfy the relation ...

  f(-x) = -f(x)

Of the given points, the set that is symmetrical about the origin is found on the 3rd graph:

  (-4, 0), (0, 0), (4, 0)