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e-lub [12.9K]
2 years ago
12

An online furniture store sells chairs for $50 each and tables for $250 each. Every day, the store can ship no more than 36 piec

es of furniture and must sell at least $3400 worth of chairs and tables. If 23 chairs were sold, determine all possible values for the number of tables that the store must sell in order to meet the requirements. Your answer should be a comma separated list of values. If there are no possible solutions , submit an empty answer.
Mathematics
1 answer:
sattari [20]2 years ago
8 0

Answer:

All possible values for the number of tables that the store must sell in order to meet the requirements are 9, 10, 11, 12, 13.

Step-by-step explanation:

Let x be the number of chairs sold and y be the number of tables sold.

Chairs are sold for $50 each, then x chairs cost $50x.

Tables are sold for $250 each, then y tables cost $250y.

In total, x chairs and y tables cost $(50x+250y).

Every day, the store can ship no more than 36 pieces, then

x+y\le 36

Every day, the store must sell at least $3,400 worth of chairs and tables, then

50x+250y\ge 3,400

If 23 chairs were sold, then x = 23. Substitute it into the inequalities:

23+y\le 36\Rightarrow y\le 13\\ \\50\cdot 23+250y\ge 3,400\Rightarrow 250y \ge 2,250,\ \ \ y\ge 9

Thus 9\le y\le 13

This means all possible values for the number of tables that the store must sell in order to meet the requirements are 9, 10, 11, 12, 13.

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∠ ABD = 5(2X+1)
∠ DBC = 3X+6
∠ EBC = Y +135/2

∠ ABD and ∠ DBC are linear pairs
∴ ∠ ABD +∠ DBC = 180
∴ 5(2X+1) + 3X+6 =180
solve for x
∴ x = 13
∴∠ ABD = 5(2X+1) = 5(2*13+1) = 135
  ∠ DBC = 3x+6  = 3*13+6 = 45

∠ ABD  and ∠ EBC are vertical angles
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∴ y +135/2 = 135
∴ y = 135/2

The <span>statements that are true:
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dmitriy555 [2]

Answer: The answer is 30%.


Step-by-step explanation:  Given that there is a group of 10 light users and 10 heavy users. We are to find the probability that exactly 3 of the 20 users are HIV positive.

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Since there is a 45% chance of a light user to be HIV positive and 55% chance of a heavy user to be HIV positive, so the required probability is given by

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Step-by-step explanation:

The first step is to find the probability of the first selection being male. This is calculated as number of male mice divided by total number of mice in the litter

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