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Marina86 [1]
2 years ago
13

A geologist is making repeated measurements (in grams) on the mass of a rock. It is not known whether the measurements are a ran

dom sample from an approximately normal population. Below are three sets of replicate measurements, listed in the order they were made. For each set of readings, state whether the assumptions necessary for the validdity of the t-test appear to be met. If the assumptions are not met, explain why?
a. 213.03 212.95 213.04 213.00 212.99 213.01 221.03 213.05
b. 213.05 213.00 212.94 213.09 212.98 213.02 213.06 212.99
c. 212.92 212.95 212.97 213.00 213.01 213.04 213.05 213.06
Mathematics
1 answer:
Rainbow [258]2 years ago
6 0

Answer:

Step-by-step explanation:

The objective of this question is to known whether the assumptions of the known data set follows normal distribution or not and if it is appropriate to use t-test or not.

TO solve this question ; we construct a box plot for the known data set by using a MINITAB software

The process is as follows to guide you:

Enter your data in the worksheet

Then select Graph→ Boxplot→ EDA→ Boxplot

Under One Y , select simple, Then click OK

In Variables , enter measurements. Then click OK

So; for the first data set (a)  213.03 212.95 213.04 213.00 212.99 213.01 221.03 213.05  as shown in the attached file  in word document for the  boxplot below;

We will observe that there is a outliner present in the data set and the measurement do not meet the normal assumption ; as a result to that ; the t-distribution is not appropriate for this data.

(b) From the document attached below; we will realize and observe that the boxplot doesn't contains an outliner. Also; it is clear and obvious that the shape of the distribution is right skewed. The measurement thus did not meet the assumptions and as a result t- distribution is not appropriate for this data.

(c)

From the document attached below; we will realize and observe that the boxplot doesn't contains an outliner. Also; it is clear and obvious that the shape of the distribution is left skewed. The measurement thus did not meet the assumptions and as a result t- distribution is not appropriate for this data.

Download docx
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Johana works in the crime lab at the New York City Police Department. A woman’s shoe was found at a crime scene. Johana measures
madam [21]

Answer:

(7, 64.33)

Step-by-step explanation:

For a woman suspect whose shoe size was found at the crime scene, the equation which can be used to predict the estimated height is given as:

y=1.19x+56,$ where:\\x = woman's shoe size\\ y= the estimated likely height of the woman in inches.

(a)Let x=7

Then:  y =1.19(7)+56=64.33

An ordered pair that is a solution to the function is (7, 64.33)

(b) The estimated height of a woman who is of shoe size 7 is 64,33 inches.

7 0
2 years ago
Enter the values for the highlighted variables to<br> complete the steps to find the sum:
Rina8888 [55]

Answer:

a=-1

b=-9

c=9

d=3

e=3

f=2

g=1.5

Step-by-step explanation:

4 0
2 years ago
n 2018, homes in East Baton Rouge (EBR) Parish sold for an average of $239,000. You take a random sample of homes in Ascension p
Olenka [21]

Answer:

Conclusion

   There is no sufficient evidence to conclude that the mean of the home prices from Ascension parish is higher than the EBR mean

Step-by-step explanation:

From the question we are told that

   The population mean for EBR is  \mu_ 1  = \$239,000

    The sample mean for Ascension parish  is \= x_2  = \$246,000

   The  p-value  is  p-value  =  0.045

     The level of significance is  \alpha = 0.01

The null hypothesis is  H_o : \mu_2  = \mu_1

The  alternative hypothesis is  H_a  :  \mu_2 > \mu_1

Here \mu_2 is the population mean for Ascension parish

   From the data given values we see that  

          p-value  >  \alpha

So we fail to reject the null hypothesis

So we conclude that there is no sufficient evidence to conclude that the mean of the home prices from Ascension parish is higher than the EBR mean

3 0
2 years ago
A guy wire is used to support flagpoles in windy areas. These wires are anchored in the ground to provide constant stability. Yo
r-ruslan [8.4K]

Answer: a) Length of wire to replace old one=9ft

b) Length of wire=3.09ft

Leftover wire=0.91ft

Step-by-step explanation: from the right angle triangle, Tan&=20/15

&=53.13°

Length of wire,x=cos 31.13=x/15

15cos31.13

X=9

b) Tan&=10/6

Tan^-110/6

&=59.05

Length= 6cos59.04

X=3.09

4-3.09=.91= leftover wire

8 0
2 years ago
A customer borrowed $2000 and then a further $1000 both repayable in 12 months. What should he have saved if he had taken out on
Neporo4naja [7]

Answer:

a. $60

Step-by-step explanation:  

We will use simple interest formula to solve our given problem.

A=P(1+rt), where

A= Amount after t years.

P= Principal amount.

r= Interest rate in decimal form.      

t= Time in years.

Let us find amount of loans repayable after 12 months for taking two amounts of $2000 and $1000.

As $2000 and $1000 are less than 2500, so the rate of loan will be 10%.

10\%=\frac{10}{100}=0.10

12 months = 1 year.

A=2000(1+0.10\times 1)

A=2000(1+0.10)

A=2000(1.10)

A=2200

Now let us find amount repayable after 12 months for borrowing $1000.

A=1000(1+0.10\times 1)

A=1000(1+0.10)

A=1000(1.10)

A=1100

Adding these amounts we will get total repayable amount after 12 months for borrowing $2000 and $1000 separately.

\text{Amount repayable for borrowing two separate amounts}=2200+1100=3300

Now let us find repayable amount after 12 months for taking 1 loan. As $3000 is between $2501 and $7500, so rate of loan will be 8%.

8\%=\frac{8}{100}=0.08

A=3000(1+0.08\times 1)

A=3000(1+0.08)

A=3000(1.08)

A=3240

Now let us find difference between both repayable loan amounts.

\text{Difference between both repayable loan amounts}=3300-3240

\text{Difference between both repayable loan amounts}=60

Therefore, the customer should have saved $60, if he had taken out one loan for $3000 and option a is the correct choice.

6 0
2 years ago
Read 2 more answers
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