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Semmy [17]
2 years ago
6

Show that x²-8x+20 can be written in the form (x-a)²+a where a is an integer

Mathematics
1 answer:
Fiesta28 [93]2 years ago
5 0

Answer:

   x² - 8x + 20

=  x²- 2*4*x + 16 + 4

=  x²- 2*4*x + 4² + 4

= (x - 4)² + 4

= (x - a)² + a, with a = 4

Hope this helps!

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The graph below represents a polynomial.
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Answer:

C

Step-by-step explanation:

The polynomial on the graph has zeros or x-intercepts at x = -3, 0, 2, 4. These come from the factors x (x+3)(x-2)(x-4). Notice at 4 it doesn't cross but just touches. This means it has a degree of 2. So the factors are x(x+3)(x-2)(x-4)^2. This matches to C.

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2 years ago
What expression represents the value of v?
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Answer

I think it is 2 or 3

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let x = the amoun of raw sugar in tons a procesing plant is a sugar refinery process in one day . suppose x can be model as expo
anygoal [31]

Answer:

The answer is below

Step-by-step explanation:

A sugar refinery has three processing plants, all receiving raw sugar in bulk. The amount of raw sugar (in tons) that one plant can process in one day can be modelled using an exponential distribution with mean of 4 tons for each of three plants. If each plant operates independently,a.Find the probability that any given plant processes more than 5 tons of raw sugar on a given day.b.Find the probability that exactly two of the three plants process more than 5 tons of raw sugar on a given day.c.How much raw sugar should be stocked for the plant each day so that the chance of running out of the raw sugar is only 0.05?

Answer: The mean (μ) of the plants is 4 tons. The probability density function of an exponential distribution is given by:

f(x)=\lambda e^{-\lambda x}\\But\ \lambda= 1/\mu=1/4 = 0.25\\Therefore:\\f(x)=0.25e^{-0.25x}\\

a) P(x > 5) = \int\limits^\infty_5 {f(x)} \, dx =\int\limits^\infty_5 {0.25e^{-0.25x}} \, dx =-e^{-0.25x}|^\infty_5=e^{-1.25}=0.2865

b) Probability that exactly two of the three plants process more than 5 tons of raw sugar on a given day can be solved when considered as a binomial.

That is P(2 of the three plant use more than five tons) = C(3,2) × [P(x > 5)]² × (1-P(x > 5)) = 3(0.2865²)(1-0.2865) = 0.1757

c) Let b be the amount of raw sugar should be stocked for the plant each day.

P(x > a) = \int\limits^\infty_a {f(x)} \, dx =\int\limits^\infty_a {0.25e^{-0.25x}} \, dx =-e^{-0.25x}|^\infty_a=e^{-0.25a}

But P(x > a) = 0.05

Therefore:

e^{-0.25a}=0.05\\ln[e^{-0.25a}]=ln(0.05)\\-0.25a=-2.9957\\a=11.98

a  ≅ 12

6 0
2 years ago
Estimate the indicated probability by using normal distribution as an approximation to the binomial distribution. Estimate P(6)
lianna [129]

Answer:

P(6) = 0.6217

Step-by-step explanation:

To find P(6), which is the probability of getting a 6 or less, we will need to first calculate two things: the mean of the sample (also known as the "expected value") and the standard deviation of the sample.  

Mean = np

Here, "n" is the sample size and "p" is the probability of the outcome of interest, which could be getting a heads when a tossing a coin, for instanc

So, Mean = n × p = (18) ×(0.30) = 5.4

Next we we will find the standard deviation:

Standard Deviation = \sqrt{npq}

n = 18  and  p = 0.3   "q" is simply the probability of the other possible outcome (maybe getting a tails when flipping a coin), so   q = 1 - p

Standard Deviation =\sqrt{npq} = \sqrt{(18)(0.3)(0.7)}  

                                                            = 1.944

Now calculate the Z score for 6 successes.  

Z = ( of successes we're interested in - Mean) ÷ (Standard Deviation)

=(6-5.4)  ÷ (1.944) = 0.309

we have our Z-score, we look on the normal distribution and find the area of the curve to the left of a Z value of 0.309.  This is basically adding up all of the possibilities for getting less than or equal to 6 successes.  So, we get 0.6217.

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2 years ago
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