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2 years ago

Mike is flying a kite with a string that is 20 ft long is flying at a height of 16 ft.

Mathematics

2 answers:

IRISSAK [1]2 years ago

7 0

Answer:

Step-by-step explanation:

We can use the Pythagorean theorem to find the answer

The lengths in the problem form a right triangle with a hypotenuse of 20ft and legs of 16ft and the horizantal distance

400-256 = 144

✓144 = 12

sladkih [1.3K]2 years ago

5 0

The answer to this is 12

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A $1,000 face value bond is currently quoted at 100.8. the bond pays semiannual payments of $22.50 each and matures in six years

gtnhenbr [62]

We are given with
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b = 22.50
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b = Fib
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The coupon rate is 2.25%

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2 years ago

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2 years ago

A software store has put some of its inventory on sale. Games are marked down by 15%, and security programs are marked down by 1

Katyanochek1 [597]

Answer:

Option D. $\$11.34$

Step-by-step explanation:

Let

x -----> the original price of one game

y ----> the original price of one security programs

Remember that

$100\%-15\%=85\%=85\100=0.85$

$100\%-18\%=82\%=82\100=0.82$

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$0.85(2x)=35.70\\1.70x=35.70\\x=\$21$

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2 years ago

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Kayleigh babysat for 11 hours this week. That was 5 fewer than 2/3 as many hours as she babysat last week, h. Write an equation

lukranit [14]

Answer: The answer is $\textup{x}=\dfrac{2}{3}\textup{h}-5.$

Step-by-step explanation: Given that Kayleigh babysat for 11 hours the present week. Also, this was 5 less than two-third of the number of hours she babysat last week, which is represented by 'h'.

We are to write an equation to represent the number of hours she babysat each week.

So, for that, let 'x' be the number of hours she babysat this week. Then, according to the question, we can write

$\textup{x}=\dfrac{2}{3}\textup{h}-5.$

Also, it is given that

$\textup{x}=11.$

Therefore,

$11=\dfrac{2}{3}\textup{h}-5\\\\\Rightarrow \dfrac{2}{3}\textup{h}=16\\\\\Rightarrow \textup{h}=24.$

Hence, using the above relation, we can find the number oh hours Keyleigh babysat each week.

Thus, the required equation is

$\textup{x}=\dfrac{2}{3}\textup{h}-5,$

where, 'x' and 'h' are the number of hours she sat this week and last week respectively.

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2 years ago

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harina [27]

8.6 = -5
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2 years ago

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