answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andre45 [30]
1 year ago
9

Credit card holders carry an average debt of $3,027 per month, with a standard deviation of $1,060. A credit card company is loo

king to drop its accounts with their customers who are not using their cards as much, that is customers whose monthly debts are in the bottom 2.5% of all accounts. Use a calculator to find how much debt must a customer have to be dropped by the credit card company if the company only looks at 30 accounts.
Mathematics
1 answer:
Alex1 year ago
7 0

Answer:

To be dropped, the client must have debts of $949.40 or lower.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

\mu = 3027, \sigma = 1060

Bottom 2.5%

The 2.5th percentile and lower.

The 2.5th percentile is X when Z has a pvalue of 0.025. So X when Z = -1.96. Then

Z = \frac{X - \mu}{\sigma}

-1.96 = \frac{X - 3027}{1060}

X - 3027 = -1.96*1060

X = 949.4

To be dropped, the client must have debts of $949.40 or lower.

You might be interested in
Find the P​-value in a test of the claim that the mean IQ score of acupuncturists is equal to​ 100, given that the test statisti
klemol [59]

Answer:

P-value = 0.0455

Step-by-step explanation:

In this question, we are concerned with calculating the P- value in a test.

Mathematically we know that;

P-value = 2 * P(Z > |z|)

Please check attachment for complete solution and by step explanation

7 0
2 years ago
Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One common ch
enot [183]

Answer:

y=\frac{-7t^2+22t-7}{7t-22}

Step-by-step explanation:

We are given that

Initial value problem

y'=(t+y)^2-1, y(3)=4

Substitute the value z=t+y

When t=3 and y=4 then

z=3+4=7

y'=z^2-1

Differentiate z w.r.t t

Then, we get

\frac{dz}{dt}=1+y'

z'=1+z^2-1=z^2

z^{-2}dz=dt

Integrate on both sides

-\frac{1}{z}dz=t+C

z=-\frac{1}{t+C}

Substitute t=3 and z=7

Then, we get

7=-\frac{1}{3+C}

21+7C=-1

7C=-1-21=-22

C=-\frac{22}{7}

Substitute the value of C then we get

z=-\frac{1}{t-\frac{22}{7}}

z=\frac{-7}{7t-22}

y=z-t

y=\frac{-7}{7t-22}-t

y=\frac{-7-7t^2+22t}{7t-22}

y=\frac{-7t^2+22t-7}{7t-22}

8 0
2 years ago
Easy question.
Nimfa-mama [501]

Answer:

Pia

Step-by-step explanation:

The smaller the number of pencils in a bundle the greater the number of  bundles.

For example if the number of pencils each has is 60,

Then the number of bundles for Pia = 60/10 = 6,

and    ...................................................Gauri  = 60/12 = 5,

and   .....................................................Yasmin = 60/20 = 3.

3 0
2 years ago
The original cost of an item is $64, but you have to pay $78.08. What is the markup of the item (as a percent)?
Neko [114]

Answer:

Step-by-step explanation:

The answer is 22 percent.

5 0
2 years ago
Dr. Miriam Johnson has been teaching accounting for over 20 years. From her experience, she knows that 60% of her students do ho
oksano4ka [1.4K]

Answer:

a) The probability that a student will do homework regularly and also pass the course = P(H n P) = 0.57

b) The probability that a student will neither do homework regularly nor will pass the course = P(H' n P') = 0.12

c) The two events, pass the course and do homework regularly, aren't mutually exclusive. Check Explanation for reasons why.

d) The two events, pass the course and do homework regularly, aren't independent. Check Explanation for reasons why.

Step-by-step explanation:

Let the event that a student does homework regularly be H.

The event that a student passes the course be P.

- 60% of her students do homework regularly

P(H) = 60% = 0.60

- 95% of the students who do their homework regularly generally pass the course

P(P|H) = 95% = 0.95

- She also knows that 85% of her students pass the course.

P(P) = 85% = 0.85

a) The probability that a student will do homework regularly and also pass the course = P(H n P)

The conditional probability of A occurring given that B has occurred, P(A|B), is given as

P(A|B) = P(A n B) ÷ P(B)

And we can write that

P(A n B) = P(A|B) × P(B)

Hence,

P(H n P) = P(P n H) = P(P|H) × P(H) = 0.95 × 0.60 = 0.57

b) The probability that a student will neither do homework regularly nor will pass the course = P(H' n P')

From Sets Theory,

P(H n P') + P(H' n P) + P(H n P) + P(H' n P') = 1

P(H n P) = 0.57 (from (a))

Note also that

P(H) = P(H n P') + P(H n P) (since the events P and P' are mutually exclusive)

0.60 = P(H n P') + 0.57

P(H n P') = 0.60 - 0.57

Also

P(P) = P(H' n P) + P(H n P) (since the events H and H' are mutually exclusive)

0.85 = P(H' n P) + 0.57

P(H' n P) = 0.85 - 0.57 = 0.28

So,

P(H n P') + P(H' n P) + P(H n P) + P(H' n P') = 1

Becomes

0.03 + 0.28 + 0.57 + P(H' n P') = 1

P(H' n P') = 1 - 0.03 - 0.57 - 0.28 = 0.12

c) Are the events "pass the course" and "do homework regularly" mutually exclusive? Explain.

Two events are said to be mutually exclusive if the two events cannot take place at the same time. The mathematical statement used to confirm the mutual exclusivity of two events A and B is that if A and B are mutually exclusive,

P(A n B) = 0.

But, P(H n P) has been calculated to be 0.57, P(H n P) = 0.57 ≠ 0.

Hence, the two events aren't mutually exclusive.

d. Are the events "pass the course" and "do homework regularly" independent? Explain

Two events are said to be independent of the probabilty of one occurring dowant depend on the probability of the other one occurring. It sis proven mathematically that two events A and B are independent when

P(A|B) = P(A)

P(B|A) = P(B)

P(A n B) = P(A) × P(B)

To check if the events pass the course and do homework regularly are mutually exclusive now.

P(P|H) = 0.95

P(P) = 0.85

P(H|P) = P(P n H) ÷ P(P) = 0.57 ÷ 0.85 = 0.671

P(H) = 0.60

P(H n P) = P(P n H)

P(P|H) = 0.95 ≠ 0.85 = P(P)

P(H|P) = 0.671 ≠ 0.60 = P(H)

P(P)×P(H) = 0.85 × 0.60 = 0.51 ≠ 0.57 = P(P n H)

None of the conditions is satisfied, hence, we can conclude that the two events are not independent.

Hope this Helps!!!

7 0
2 years ago
Other questions:
  • Find the thirty-second term of the following sequence.<br> 9, 15, 21, ...<br> 186<br> 199<br> 195
    8·2 answers
  • Erika calculated that she would spend $115 on school supplies this year. She actually spent $82.50 on school supplies. What is E
    7·2 answers
  • Charlie has the utility function u(xa, xb) =xaxb.his indifference curve passing through 32 applesand 8 bananas will also pass th
    11·1 answer
  • The path of a race will be drawn on a coordinate grid like the one shown below. The starting point of the race will be at (−5.5,
    5·1 answer
  • N a circle with a radius of 2.8 cm, an arc is intercepted by a central angle of π5 radians. what is the arc length? use 3.14 for
    10·2 answers
  • Complete the sentence. the roots of the equation x^2 - 8x - 48 = 0 are -4 and *blank*
    14·2 answers
  • What type of polynomial is 5x+1
    14·1 answer
  • Coordinates, gradient and tangent work (see image).
    6·1 answer
  • Solve for x in the equation x squared minus 14 x + 31 = 63.
    12·2 answers
  • Tony made 14 L of lemonade for a party. His guests drank 9,500mL, start of the lemonade.
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!