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Solnce55 [7]
2 years ago
9

Attraction Corporation produces specially machined parts. The parts are produced in batches in one continuous manufacturing proc

ess. Each part is custom produced and requires special engineering design activity (based on customer specifications). Once the design is completed, the equipment can be set up for batch production. Once the batch is completed, a sample is taken and inspected to see if the parts are within the tolerances allowed. Thus, the manufacturing process has four activities: engineering, setups, machining, and inspecting. In addition, there is a sustaining process with two activities: providing utilities (plantwide) and providing space. Costs have been assigned to each activity using direct tracing and resource drivers:Engineering $1,000,000Setups 900,000Machining 2,000,000Inspection 800,000Providing space 250,000Providing utilities 180,000Activity drivers for each activity have been identified and their practical capacities listed:Machine hours 25,000Setups 200Engineering hours 5,000Inspection hours 2,500The costs of facility-level activities are assigned using machine hours.What is (are) the unit-level activity(ies)?a. setups.b. providing space.c. machining.d. engineering.
Business
1 answer:
Juliette [100K]2 years ago
3 0

Answer:

c. machining.

Explanation:

Unit level activities take place in order to manufacture the product. This manufacturing process has four activities:

  • engineering
  • setups
  • machining
  • inspecting

Unit level activities depend  on the amount of units produced, this means that as more units are produced, more costs will be allocated. In this case, engineering, setups and inspecting are done on a batch basis, which means that they are batch level activities.

Only machining costs are proportional to the number of units produced.

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The Lumbar Chair Company manufacturers a standard recliner. During February, the firm's Assembly Department started production o
Irina-Kira [14]

Answer:

115,000 chairs

Explanation:

Calculation to determine How many of the chairs that were started were also completed during February

Using this formula

Chairs started and Completed=Beginning chairs production-Ending chairs production

Let plug in the formula

Chairs started and Completed=140,000 chairs- 25,000 chairs

Chairs started and Completed= 115,000 chairs

Therefore The numbers of chairs that were started and were also completed during February will be 115,000 chairs

3 0
1 year ago
Delray Manufacturing needs to better budget and analyze costs. While Delray has experienced high sales growth, it has struggled
dusya [7]

Answer  and Explanation:

1.

Direct Material budget  

April May June

Budgeted Production (Units) 880 1100 1075

Material required per unit (Pounds)4 4 4

Materials needed for production 3520 4400 4300

Add : Desired Ending Inventory 1760 1720 1800

Total Material Requirements (Pounds) 5280 6120 6100

Less : Beginning Inventory 1408 1760 1720

Materials to be purchased (pounds) 3872 4360 4380

Material price per pound $ 3 $ 3 $  3

Budgeted Cost of direct material purchases $     11,616 $        13,080 $       13,140

Ending Inventory is 40% of next month production needs

Ending inventory for June can be analysed from chart given above which shows 1800, therefore production for July is = 1800/40% = 4500 units

Beginning Inventory is taken as 40% of current months

2.

Direct Material budget  

April May June

Budgeted Production (Units) 880 1100 1075

Material required per unit (Pounds) 4 4 4

Materials needed for production 3520 4400 4300

Add : Desired Ending Inventory 1540 1505 1575

Total Material Requirements (Pounds) 5060 5905 5875

Less : Beginning Inventory 1408 1540 1505

Materials to be purchased (pounds) 3652 4365 4370

Material price per pound $  3 $   3 $  3

Budgeted Cost of direct material purchases $     10,956 $        13,095 $    13,110

Budgeted cost for april will therefore down, as less material is required and needed to be purchased.

4 0
1 year ago
A parent holding company sells shares in its subsidiary such that the parent now owns only 65% of the subsidiary and, thus, the
natita [175]

Answer:

correct option is a) 10.2%; $2,245,000

Explanation:

given data

Gross dividends = $2,500,000

tax rate = 34%

inter company dividends = 70%

to find out

effective tax rate and net dividends

solution

Effective tax rate = (1 - Exclusion) × (Tax rate)    ............1

Effective tax rate =  (1 – 0.70) × (0.34)  

Effective tax rate = 10.2 %

and

net dividends = Gross dividends - Tax     ..................2

net dividends = $2,500,000 - [ $2,500,000 (1 – 0.70)×(0.34)  ]

net dividends = $2,500,000 – $255,000

net dividends = $2,245,000

so correct option is a) 10.2%; $2,245,000

7 0
1 year ago
Read 2 more answers
Suppose a manufacturing plant is considering three options for expansion. The first one is to expand into a new plant (large), t
sp2606 [1]

Answer:

a. $50,000

b. $77,500

c. $27,500

d. Large expansion or plant

Explanation:

a. What is the highest Expected Monetary Value (EMV)?

1. EMV of Large expansion = ($100000×0.50) + ($10000×0.25) + (-$10000×0.25)

EMV of Large expansion =

2. EMV of Medium expansion = ($40000×0.50) + ($40000×0.25) + ($5000×0.25)

EMV of Medium expansion = $31,250

3. EMV of Small expansion = ($15000×0.50) + ($15000×0.25) + ($15000×0.25)

EMV of Small expansion = $15,000

The highest EMV is $50,000 which is the EMV of Large expansion.

b. What is Expected Value with Perfect Information (EVwPI)?

EVwPI is obtained by adding together the expected value of the highest profit from each of the expansions as follows:

EVwPI = ($100000×0.50) + ($40000×0.50) + ($15000×0.50)

EVwPI = $77,500

c. What is the organization willing to pay for perfect information?

This requires the calculation of Expected Value of Perfect Information (EVPI). This can be obtained as follows:

EVPI = EVwPI - EVwoPI

Where EVwoPI denotes Expected Value without Perfect Information and it is is the highest EMV of $50,000 which is the EMV of Large expansion obtained in a above.

Substituting the figures, we have:

EVPI = $77,500 - $50,000 = $27,500

d. Which of the expansion plans should the manager choose?

The manager should choose the large expansion because it has the highest or maximum EMV of $50,000.

4 0
1 year ago
Read 2 more answers
Each machine must be run by one of 19 cross-trained workers who are each available 35 hours per week. The plant has 10 type 1 ma
Mrac [35]

Answer:

The Linear programming model is given as below

Profit Function: P=90X+120Y+150Z

Constraints:

2X+2Y+Z\leq 400

3X+4Y+6Z\leq 240

4X+6Y+5Z\leq 320

\dfrac{2X+2Y+Z}{40}\leq 10

\dfrac{3X+4Y+6Z}{40}\leq 6

\dfrac{4X+6Y+5Z}{40}\leq 8

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

Explanation:

As the question is not complete, the complete question is found online and is attached herewith.

Let the number of product 1 to be produced is X, that of product 2 is Y and product 3 is Z

so  the maximizing function is the profit function which is given as

P=90X+120Y+150Z

Now as the number of hours in a week are 40 and there are a total of 10 type 1 machines so the total number of machine 1 hours are 40*10=400 hours

As from the given table product 1 uses 2 machine hours of machine 1, product 2 uses 2 machine hours of machine 1 and product 3 uses 1 hour of machine 1 so

2X+2Y+Z\leq 400

Now as the number of hours in a week are 40 and there are a total of 6 type 2 machines so the total number of machine 2 hours are 40*6=240 hours

As from the given table product 1 uses 3 machine hours of machine 2, product 2 uses 4 machine hours of machine 2 and product 3 uses 6 hour of machine 2 so

3X+4Y+6Z\leq 240

Now as the number of hours in a week are 40 and there are a total of 8 type 3 machines so the total number of machine 3 hours are 40*8=320 hours

As from the given table product 1 uses 4 machine hours of machine 3, product 2 uses 6 machine hours of machine 3 and product 3 uses 5 hour of machine 3 so

4X+6Y+5Z\leq 320

Now as the machine 1 is used as 2X+2Y+Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{2X+2Y+Z}{40}\leq 10

Now as the machine 2 is used as 3X+4Y+6Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{3X+4Y+6Z}{40}\leq 6

Now as the machine 3 is used as 4X+6Y+5Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{4X+6Y+5Z}{40}\leq 8

Now the workers are available for 35 hours so the worker available at the machine 1 is given as

\dfrac{2X+2Y+Z}{35}

That of machine 2 is given as

\dfrac{3X+4Y+6Z}{35}

That of machine 3 is given as

\dfrac{4X+6Y+5Z}{35}

As the total number of workers is 19 so the constraint is given as

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

So the Linear programming model is given as below

Profit Function: P=90X+120Y+150Z

Constraints:

2X+2Y+Z\leq 400

3X+4Y+6Z\leq 240

4X+6Y+5Z\leq 320

\dfrac{2X+2Y+Z}{40}\leq 10

\dfrac{3X+4Y+6Z}{40}\leq 6

\dfrac{4X+6Y+5Z}{40}\leq 8

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

4 0
2 years ago
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