For the Address Block 195.200.0.0/16 a. If you have 320 Customers that need 128 addresses/customer - will there be enough addres
1 answer:
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Answer:
A Program was written to carry out some set activities. below is the code program in C++ in the explanation section
Explanation:
Solution
CODE
#include <iostream>
using namespace std;
int main() {
string name; // variables
int number;
cin >> name >> number; // taking user input
while(number != 0)
{
// printing output
cout << "Eating " << number << " " << name << " a day keeps the doctor away." << endl;
// taking user input again
cin >> name >> number;
}
}
Note: Kindly find an attached copy of the compiled program output to this question.
Answer:
<em>import java.util.Scanner;</em>
<em>public class TestClass {</em>
<em> public static void main(String[] args) {</em>
<em> Scanner input = new Scanner(System.in);</em>
<em> System.out.println("Enter value for x1, x2, y1, y2");</em>
<em> double x1 = input.nextDouble();</em>
<em> double x2 = input.nextDouble();</em>
<em> double y1 = input.nextDouble();</em>
<em> double y2 = input.nextDouble();</em>
<em> double xVal = Math.pow((x2-x1),2);</em>
<em> double yVal = Math.pow((y2-y1),2);</em>
<em> double distance = Math.sqrt(xVal+yVal);</em>
<em> System.out.println(distance);</em>
<em> }</em>
<em>}</em>
Explanation:
The code is written in Java Programming Language.
This code simply implements the formula for the distance between two points given as
distance =
The scanner class is used to prompt and receive all the variables that are declared.
Note that we used two special Java methods (Math.pow and Math.sqrt)