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morpeh [17]
2 years ago
3

Automated implementation of an application's build, test, and deployment process is called as _____________________.

Computers and Technology
1 answer:
liubo4ka [24]2 years ago
8 0

Answer:

Deployment pipeline.

Explanation:

Automated implementation of an application's build, test, and deployment process is called as deployment pipeline.

Generally, the main components of the deployment pipeline are the; build automation, test automation and deployment automation.

The main purpose why software engineers use the deployment pipeline is to enable them avoid any waste in the software development process, and to avail them the opportunity to give a rapid feedback to the production team during deployment of the software application. This ultimately implies that it involves the process of picking up a code from version control and presenting it to the end users of the software application in an automated manner.

Since, it is done automatically it helps to mitigate human errors and to meet customer's requirements.

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What is the distance rn between the point of application of n⃗ and the axis of rotation? what is the distance rw between the poi
Mandarinka [93]

Complete Question.

A. Suppose that you are holding a pencil balanced on its point. If you release the pencil and it begins to fall, what will be the angular acceleration when it has an angle of 10.0 degrees from the vertical?

B. What is the distance rn between the point of application of n⃗ and the axis of rotation?

C. What is the distance rw between the point of application of w⃗ and the axis? enter your answers in meters separated by a comma?

Answer:

A. â = - 17rad/s²

B. rn = 0, meters

C. rw = 0.074, meters

Explanation:

Where;

l = length of the pencil

θ = angle between the vertical line and the pencil

â = angular acceleration.

The torque due to weight about the pivotal point is negative since it's clockwise;

t = - mg(l/2)sinØ ..... equation 1

torque with respect to angular acceleration;

t = Iâ ..... equation 2

The moment of Inertia of the pencil about one end;

I = (ml²)/3

Substituting I into equation 2;

t = [(ml²)/3]×â

Equating the equation, we have;

[(ml²)/3]×â = - mg(l/2)sinØ

â = (-3gsinØ)/2l

â = (-3*9.8*sin10°)/(2*0.15)

Angular acceleration, â = -17rad/s²

B. The normal force is acting at the normal force only, so the distance r n between the point of application of n ⃗ and the axis of rotation is zero because the axis of pencil is passing the same point of application w.

C. rn = (lcosØ)/2

rn = (0.15 * cos10°)/2

rn = (0.15 * 0.9848)/2

rn = (0.1477)/2

rn = 0.074m.

Since the gravity acts at exactly half of the length of pencil, distance r w between the point of application of w⃗ and the axis equals 0.074m.

8 0
2 years ago
#You may modify the lines of code above, but don't move them! #When you Submit your code, we'll change these lines to #assign di
Musya8 [376]

Answer:

The solution code is written in Python:

  1. mystery_string = "Programming"
  2. output = ""
  3. for x in mystery_string:
  4.    output += x  
  5.    print(output)

Explanation:

Firstly, create a variable mystery_string to hold a random string (Line 1).

Create an output variable to hold an output string (Line 2).

Create a for-loop to traverse the mystery_string character by character (Line 4). In the iteration, get a character from the mystery_string, and concatenate it with output string (Line 5). Print the output string (Line 6) before proceed to the next iteration.

8 0
2 years ago
Suppose that the data mining task is to cluster points (with (x, y) representing location) into three clusters, where the points
solong [7]

Answer:

Explanation:

K- is the working procedure:

It takes n no. of predefined cluster as input and data points.

It also randomly initiate n centers of the clusters.

In this case the initial centers are given.

Steps you can follow

Step 1. Find distance of each data points from each centers.

Step 2. Assign each data point to the cluster with whose center is nearest to this data point.

Step 3. After assigning all data points calculate center of the cluster by taking mean of data points in cluster.

repeat above steps until the center in previous iteration and next iteration become same.

A1(4,8), A2(2, 4), A3(1, 7), B1(5, 4), B2(5,7), B3(6, 6), C1(3, 7), C2(7,8)

Centers are X1=A1, X2=B1, X3=C1

A1 will be assigned to cluster1, B1 will be assigned to cluster2 ,C1 will be assigned to cluster3.

Go through the attachment for the solution.

5 0
2 years ago
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