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Bond [772]
2 years ago
11

Suppose the probability of an IRS audit is 3.8 percent for U.S. taxpayers who file form 1040 and who earned $100,000 or more. Wh

at are the odds that such a taxpayer will be audited? (Round your answers to the nearest whole number.) What are the odds against such a taxpayer being audited? (Round your answers to the nearest whole number.)
Mathematics
1 answer:
brilliants [131]2 years ago
5 0

Answer:

a) The odds that such a taxpayer will be audited is 4%.

b) The odds against such a taxpayer being audited is 96%.

Step-by-step explanation:

a) Data and Calculations:

The probability of an IRS audit = 3.8% for U.S. taxpayers who file form 1040 and earned $100,000.

This is the same as the odds that such a taxpayer will be audited.  Odds is the likelihood or chance that an event will take place.

b) The probability of not being audited is 100 - 3.8% = 96.2%

The odd against being audited is the likelihood or chance that an event will not take place.

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bixtya [17]
A
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Those are your answers.
5 0
2 years ago
Read 2 more answers
A rectangular portrait measures 50cm by 70cm. It is surrounded by a rectangular frame of uniform width. If the area of the frame
snow_tiger [21]

Let us assume uniform width = x cm wide.

Length of rectangular portrait = 50cm and width of rectangular portrait = 70cm.

Therefore,  length of rectangle made by frame = 50 + x+x = (2x+50) cm.

And width of rectangle made by frame = 70+x+x = (2x+70) cm.

We know, the area of rectangular portrait = 50 × 70 = 3500 cm^2.

Total area of the rectangle made by frame would be =  (2x+50) * (2x+70)

We know,

Actual area of frame = Area of rectangle made by frame -  area of rectangular portrait.

We also given "the area of the frame is the same as the area of the portrait."

We can setup an equation now,

 3500 = (2x+50) * (2x+70) - 3500.

Subtracting 3500 from both sides, we get

3500-3500 = (2x+50) * (2x+70) - 3500-3500.

0 = (2x+50) * (2x+70) -7000.

FOIL (2x+50) * (2x+70), we get

0 = 2x*2x +2x*70 + 50*2x +50*70 - 7000.

0 = 4x^2 +140x +100x +3500 -7000.

4x^2 +240x -3500 = 0.

Dividing whole equation by 4, we get

x^2 +60x - 875 =0

Applying quadratic formula =\frac{-b\pm \sqrt{b^2-4ac}}{2a}, we get

=\frac{-60\pm \sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}

x=\frac{-60+\sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}=5\left(\sqrt{71}-6\right)

x=\frac{-60-\sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}:\quad -5\left(6+\sqrt{71}\right)

We cant take negative value.

So, x=5\left(\sqrt{71}-6\right)=12.13

We could take approximately 12 cm.



7 0
2 years ago
A consumer protection agency is testing a sample of cans of tomato soup from a company. If they find evidence that the average l
EastWind [94]

Answer:

I think it might be a bit I'm not sure

3 0
2 years ago
Round each weight to the nearest whole gram. Then estimate the total weight of the coins in Allen’s hand. 2.500,5.000,2.268,5.67
irina1246 [14]
So the rounded weights would be 3, 5, 2, 6, and 11, as when you round, you look at the number to the right of the one you want to round to. If it's 5 or larger, you add one to the spot you're rounding to, and make the rest of the numbers after into zeroes. If it's below 5, just change the ones after the one you want to round to into zeroes and don't add one.

Then for the estimating of the weight, you would add them together. 3+5+2+6+11. That would equal 27, so the estimate weight is 27 grams.
8 0
2 years ago
Suppose you have a litter of mice which consists of 8 males and 4 females. If you randomly grab two of them, what is the probabi
tiny-mole [99]

Answer:

The probability that they are both male is 0.424 (3 d.p.)

Step-by-step explanation:

The first step is to find the probability of the first selection being male. This is calculated as number of male mice divided by total number of mice in the litter

Prob (1st male) = 8 ÷ 12 = 0.667

Next is to find the probability of the second selection also being male. Note that the question states that the first mice was selected without replacement. This means the first mouse taken results in a reduction in both the number of male mice and total number of mice in the litter.

Prob (2nd male) = (8 - 1) ÷ (12 - 1) = 7/11 = 0.636

Therefore,

Prob (1st male & 2nd male) = 0.667 × 0.636 = 0.424

5 0
2 years ago
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