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Alexus [3.1K]
2 years ago
15

Suppose you have a litter of mice which consists of 8 males and 4 females. If you randomly grab two of them, what is the probabi

lity that they are both male? You may think of this questions as without replacement. Keep your answer in decimal form and round to THREE decimal places.
Mathematics
1 answer:
tiny-mole [99]2 years ago
5 0

Answer:

The probability that they are both male is 0.424 (3 d.p.)

Step-by-step explanation:

The first step is to find the probability of the first selection being male. This is calculated as number of male mice divided by total number of mice in the litter

Prob (1st male) = 8 ÷ 12 = 0.667

Next is to find the probability of the second selection also being male. Note that the question states that the first mice was selected without replacement. This means the first mouse taken results in a reduction in both the number of male mice and total number of mice in the litter.

Prob (2nd male) = (8 - 1) ÷ (12 - 1) = 7/11 = 0.636

Therefore,

Prob (1st male & 2nd male) = 0.667 × 0.636 = 0.424

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Step-by-step explanation:

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A cement bridge post is 24 inches square and 15 feet 9 inches in length. If the cement weighs 145 pounds per cubic foot, how muc
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Answer:

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Step-by-step explanation:

Step 1: Get the total volume of a cement bridge post

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Volume of cement bridge post=Base area×Length

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Convert 24 inches to foot=24/12=2^2=4 feet²

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replacing;

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Volume of cement bridge post=63 cubic feet

Step 2: Get the total weight of the cement bridge post

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Step-by-step explanation:

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