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Alexus [3.1K]
2 years ago
15

Suppose you have a litter of mice which consists of 8 males and 4 females. If you randomly grab two of them, what is the probabi

lity that they are both male? You may think of this questions as without replacement. Keep your answer in decimal form and round to THREE decimal places.
Mathematics
1 answer:
tiny-mole [99]2 years ago
5 0

Answer:

The probability that they are both male is 0.424 (3 d.p.)

Step-by-step explanation:

The first step is to find the probability of the first selection being male. This is calculated as number of male mice divided by total number of mice in the litter

Prob (1st male) = 8 ÷ 12 = 0.667

Next is to find the probability of the second selection also being male. Note that the question states that the first mice was selected without replacement. This means the first mouse taken results in a reduction in both the number of male mice and total number of mice in the litter.

Prob (2nd male) = (8 - 1) ÷ (12 - 1) = 7/11 = 0.636

Therefore,

Prob (1st male & 2nd male) = 0.667 × 0.636 = 0.424

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<h3 /><h3>Explanation: </h3>

Predict how much money can be saved without having a negative actual net income.

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Budgeted Amount  (is an itemized allotment of funds, time for a given period)

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How much money can be saved without having a negative actual net income?

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  • c.  $200 can be saved resulting in an actual net income of $150.
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Learn more about   money brainly.com/question/1870710

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From the given graph, the lines f(x) and g(x) intersects at two different points.

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The diagonal AD divides the quadrilateral in two triangles:

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Area of a triangle is given as:

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Using these values, we get:

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