Answer:
The dimensions that minimize the surface are:
Wide: 1.65 yd
Long: 3.30 yd
Height: 2.20 yd
Step-by-step explanation:
We have a rectangular base, that its twice as long as it is wide.
It must hold 12 yd^3 of debris.
We have to minimize the surface area, subjet to the restriction of volume (12 yd^3).
The surface is equal to:

The volume restriction is:

If we replace h in the surface equation, we have:

To optimize, we derive and equal to zero:
![dS/dw=36(-1)w^{-2} + 8w=0\\\\36w^{-2}=8w\\\\w^3=36/8=4.5\\\\w=\sqrt[3]{4.5} =1.65](https://tex.z-dn.net/?f=dS%2Fdw%3D36%28-1%29w%5E%7B-2%7D%20%2B%208w%3D0%5C%5C%5C%5C36w%5E%7B-2%7D%3D8w%5C%5C%5C%5Cw%5E3%3D36%2F8%3D4.5%5C%5C%5C%5Cw%3D%5Csqrt%5B3%5D%7B4.5%7D%20%3D1.65)
Then, the height h is:

The dimensions that minimize the surface are:
Wide: 1.65 yd
Long: 3.30 yd
Height: 2.20 yd
S(p)=D(p)
400-4p+0.00002p4=2,800-0.0012p3
Solve for p
P=96.24
$180 is the cost of the goal, and $15 is the cost of each soccer ball.
The factorization of the expression of 43x³ + 216y³ is
(7x + 6y)(49x² - 42xy + 36y²)
Step-by-step explanation:
The sum of two cubes has two factors:
1. The first factor is
+ ![\sqrt[3]{2nd}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2nd%7D)
2. The second factor is (
)² - (
) (
) + (
)²
Ex: The expression a³ + b³ is the sum of 2 cubes
The factorization of a³ + b³ is (a + b)(a² - ab + b²)
∵ The expression is 343x³ + 216y³
∵
= 7x
∵
= 6y
∴ The first factor is (7x + 6y)
∵ (7x)² = 49x²
∵ (7x)(6y) = 42xy
∵ (6y)² = 36y²
∴ The second factor is (49x² - 42xy + 36y²)
∴ The factorization of 43x³ + 216y³ is (7x + 6y)(49x² - 42xy + 36y²)
The factorization of the expression of 43x³ + 216y³ is
(7x + 6y)(49x² - 42xy + 36y²)
Learn more:
You can learn more about factors in brainly.com/question/10771256
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Okay,
Both games are: 35
First game: ?
Second game: 6 more than the first.
So,
first we subtract 6 from 35.
35 - 6 = 29
Divide by 2.
49 divided by 2 = 14.5
Add the 6 point= 14.5 + 6 = 20.5
To make sure add.
First game: 14.5
Second game:20.5
14.5 + 20.5 = 35