Answer:
The answer is meiosis 1 in Mother, meiosis 1 in father and meiosis 2 in father.
Explanation:
During meiosis, if an haploid sperm fertilizes an haploid egg that has gone through nondisjunction, there is a possibility that the offsprings genotype will by Aaa.
Also in an haploid sperm ferlilizes egg that has gone through nondisjunction in meiosis 2, the offsprings might have AAA genotype.
This is because During meiosis I, homologous chromosomes separate. If nondisjunction occurs in meiosis 1, the two homologous chromosomes move into the same daughter cell and not different daughter cells.
If this occur in the mother, both X chromosomes will all be in one cell, and there will be no X chromosome in the other cell.
If this happens in the father, both the X and Y chromosome will also be in one cell, and there will be no sex chromosome in the other cell. In this cases it is possible for a parent not to give a sex chromosome to a child and if this occur it can result in Turner syndrome with the child having XO.
During meiosis 2,sister chromatids separate. If nondisjunction happens, the two sister chromatids will move into the same daughter cell, instead of different daughter cells.
If this happens in the mother, two identical copies of an X chromosome will be in one cell, and there will not be X chromosome in the other cell and also If this happens in the father, non of the two identical copies of the X chromosome will be in one cell, with no sex chromosome in the other cell or two identical copies of the Y chromosome later be in a single cell, and there will not be sex chromosome in the other cell. In this cases it is possible for a parent not to give a sex chromosome to a child and if this occur it can result in Turner syndrome with the child having XO
