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OLEGan [10]
2 years ago
9

Angela shared a cab with her friends. When they arrived at their destination, they evenly divided the $63fare among the x of the

m. Angela also paid a $8tip. How much did Angela pay in total? Write your answer as an expression
Mathematics
1 answer:
Tresset [83]2 years ago
3 0

1.if tip included in fare, total amount paid by Angela =(55$/x) +8$

if tip is not included in fare than total amount paid by angela = (63$/x)+8$

Explanation :-

According to qus

Total friends included Angela = x

Total fare paid by them =63$

If tip included in total fare, than total fare without tip=63-8

= 55$

Sothat,

amont paid by individual =total fare /total friends. 55$/x

If tip not include in total fare than total amount paid by individual =63$/x

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7. If W = 3Z, and Z is 30% of R, then W is what
dem82 [27]

Answer:

90%

Step-by-step explanation:

Let R = 100

Since, Z = 30% of R

Therefore, Z = 30% *100 = 30

Since, W = 3Z

Therefore, W = 3*30 = 90

Percentage of W of R

= \frac{Value \: of \: W}{Value \: of \: R} \times 100\\\\=\frac{90}{100} \times 100\\\\Percentage \:of \:W \:of \:R =90\%

7 0
2 years ago
7. If SK = 13x - 5, KY= 2x + 9, and SY = 36-x, find each value.
sweet [91]

Answer:

SY=34, SK=21 and KY=13

Step-by-step explanation:

we have that

SY=SK+KY

substitute the given values

(36-x)=(13x-5)+(2x+9)

solve for x

36-x=15x+4

15x+x=36-4

16x=32

x=2

<em>Find the value of SY</em>

SY=(36-x)=36-2=34

<em>Find the value of SK</em>

SK=(13x-5)=13(2)-5=21

<em>Find the value of KY</em>

KY=(2x+9)=2(2)+9=13

5 0
2 years ago
Which property does each equation demonstrate? x2 + 2x = 2x + x2 (3z4 + 2z3) – (2z4 + z3) = z4 + z3 (2x2 + 7x) + (2y2 + 6y) = (2
myrzilka [38]

Answer:

1 . Closure

2. Distributive

3. Closure

Step-by-step explanation:

Here, we want to know the type of property exhibited or displayed by each of the equations in the question.

Equation 1 displays the closure property.

What this means that if we make an addition operation either way, we would get same answer. So we say that addition is closed for that equation.

Equation 3 exhibits closure property as well. If we go either way on the addition operation for that equation, we are bound to get the same answer.

Equation 2 exhibits the distributive property.

Each term in the bracket is multiplied by the subtraction symbol before we proceeded to complete the arithmetic operations

5 0
2 years ago
When circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%. Let
vladimir1956 [14]

Answer:

a) P(X ≤ 2) = 0.87

b)  P(X ≥ 5) = 0.01

c) P(1 ≤ X ≤ 4) = 0.71

d) P ( X = 0 ) = 0.28

e) σ(X) = 1.09 , E(X) = 1.25

Step-by-step explanation:

Given:

- Let X = the number of defective boards in a random sample of size n = 25, so X ~ Bin(25, 0.05)

Where, n = 25 and p = 0.05

Find:

(a) Determine P(X ≤ 2).(b) Determine P(X ≥ 5).(c) Determine P(1 ≤ X ≤ 4).(d) What is the probability that none of the 25 boards is defective?(e) Calculate the expected value and standard deviation of X.

Solution:

- The probability mass function for a binomial distribution is given by:

                         P ( X = x ) = nCr * (p)^r * ( 1 - p )^(n-r)

a) P(X ≤ 2):

                         P(X ≤ 2) = P ( X = 0 ) + P ( X = 1 ) + P ( X = 2 )

                         = (0.95)^25 + 25*0.05*0.95^24 + 25C2*0.05^2*0.95^23

                         = 0.87

b) P(X ≥ 5):

            P(X ≥ 5) = 1 - [P ( X = 0 ) + P ( X = 1 ) + P ( X = 2 ) + P ( X = 3 ) + P(X=4)

            = 1 - [ 0.87 + 25C3*0.05^3*0.95^22 + 25C4*0.05^4*0.95^21]

            = 1 - 0.98994

            = 0.01

c) P(1 ≤ X ≤ 4):

            P(1 ≤ X ≤ 4) = P ( X = 1 ) + P ( X = 2 ) + P ( X = 3 ) + P(X=4)

            = ( 0.87 - 0.95^25) + 0.11994

           = 0.71

d) P( X = 0 )

            P ( X = 0 ) = 0.95^25 = 0.28

e) E(X) & σ(X):

            E(X) = n*p

            E(X) = 25*0.05 = 1.25

            σ(X) = sqrt ( Var (X) )

            σ(X) = sqrt ( n*p*(1-p) ) = sqrt ( 25*0.05*0.95 )

            σ(X) = 1.09

4 0
2 years ago
Mai spends 7 and 3/5 hours in school each day. Her lunch period is 30 minutes long, and she spends a total of 42 minutes switchi
Sonja [21]
First, we solve for the number of minutes in 7 and 3/5 hours by multiplying the number by 60 giving us,
                            (7 + 3/5) x (60) = 456 minutes
Spending 30 minutes for lunch will leave her with 426 minutes. Then, spending 42 minutes for switching of classes will finally give her 414 minutes. 

We then divide this value by 6 (for her 6 classes) giving us 69 minutes. Thus, each class is 69 minutes long. 
8 0
2 years ago
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