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love history [14]
2 years ago
10

Which of the following sets contains all roots of the polynomial f(x)=2x^3+3x^2-3x-2?

Mathematics
1 answer:
svlad2 [7]2 years ago
4 0

Answer:

C

Step-by-step explanation:

Given

f(x) = 2x³ + 3x² - 3x - 2

Note that

f(1) = 2 + 3 - 3 - 2 = 0 , thus

(x - 1) is a factor

Dividing f(x) by (x - 1) gives

f(x) = (x - 1)(2x² + 5x + 2) = (x - 1)(x + 2)(2x + 1)

To find the roots equate f(x) to zero, that is

(x - 1)(x + 2)(2x + 1) = 0

Equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

x + 2 = 0 ⇒ x = - 2

2x + 1 = 0 ⇒ 2x = - 1 ⇒ x = - \frac{1}{2}

The solution set is therefore

{ - 2, - \frac{1}{2}, 1 } → C

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<u>Answer</u>:  If 15% of the customer's total is $22.05, then the customer's total is <u>$147</u>.

<u>Step-by-step explanation</u>:

Let x be the customer's total amount.

It is given that 15% of the customer's total = $22.05

⇒15% of x= $22.05

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Therefore, If 15% of the customer's total is $22.05, then the customer's total is <u>$147</u>.

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Order the expressions from least value to greatest value.
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You have to answer all of the equations first

-4.8 • 3.2 = -15.36 (negative times a positive is negative)


2 1/4 + (-1 2/5) first find a common denominator, which would be 20

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Nine new employees, two of whom are married to each other, are to be assigned nine desks that are lined up in a row. If the assi
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Answer:

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Step-by-step explanation:

The key to answering this question is considering the fact that the two married employees be treated as a single unit.

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