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2 years ago

4

Drag each step and justification to the correct location on the table. Each step and justification can be used more than once, b

ut not all steps and justifications will be used.
Order each step and justification that is needed to solve the equation below.

please help me

1 answer:

Vedmedyk [2.9K]2 years ago

4 0

Answer/Step-by-step explanation:

Below are the steps to take in solving the given equation, as well as justification forf each step:

$\frac{2}{3}y + 15 = 9$ => Given

$\frac{2}{3}y + 15 - 15 = 9 - 15$ => subtraction property of equality

$\frac{2}{3}y = - 6$ => simplification

$\frac{2}{3}y * \frac{3}{2} = - 6 * \frac{3}{2}$ => multiplication property of equality

$y = - 9$ => simplification

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The scores of the students on a standardized test are normally distributed, with a mean of 500 and a standard deviation of 110.

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σ = 110, population stadard deviation

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Read 2 more answers

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Answer:

For this case the statistic calculated is $t= 1.37$

$p_v =0.17$

So the p value is a very high value and using the significance level given $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and there is enough evidence to conclude that we have a difference between the two means at 10% of significance.

Step-by-step explanation:

Data given and notation

$\bar X_{A}$ represent the mean for the sample for A

$\bar X_{B}$ represent the mean for the sample B

$s_{A}$ represent the sample standard deviation for the sample A

$s_{B}=$ represent the sample standard deviation for the sample B

$n_{A}=20$ sample size for the group poisoned

$n_{B}=20$ sample size for the group unpoisoned

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the two means are equal or not , the system of hypothesis would be:

Null hypothesis: $\mu_{A} - \mu_{B} =0$

Alternative hypothesis: $\mu_{A} - \mu_{B} \neq 0$

For this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{A}-\bar X_{B}}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

For this case the statistic calculated is $t= 1.37$

Statistical decision

The significance level is 0.1 $\alpha=0.1$ , but we can calculate the p value for this test. The first step is calculate the degrees of freedom, on this case:

$df=n_{A}+n_{B}-2$

The p value on this case is given

$p_v =0.17$

So the p value is a very high value and using the significance level given $\alpha=0,1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and there is enough evidence to conclude that we have a difference between the two means at 10% of significance.

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