Answer:
a) Number of hours it takes 1 centimetre of snow to form in Harper's yard = (1/5) hour = 0.20 hour
b) Centimetres of snow that accumulate per hour = 5 cm
Step-by-step explanation:
Complete Question
We can calculate the depth d of snow, in centimeters, that accumulates in Harper's yard during the first h hours of a snowstorm using the equation d=5h.
a) How many hours does it take for 1 centimeter of snow to accumulate in Harper's yard? hours
b) How many centimeters of snow accumulate per hour? centimeters
Solution
The depth of snow, d, in centimetres that accumulates in Harper's yard in h hours is given d = 5h
a) Number of hours it takes 1 centimetre of snow to form in Harper's yard.
d = 5h
d = 1 cm
h = ?
1 = 5h
h = (1/5) = 0.20 hour
b) Centimetres of snow that accumulate per hour.
d = 5h
In 1 hour, h = 1 hour
d = ?
d = 5 × 1 = 5 cm
Hope this Helps!!!
Answer:
<h2>No table shows one-to-one function</h2>
Step-by-step explanation:
<em>One-to-one function is a function that preserves distinctness: it never maps distinct elements of its domain to the same element of its codomain. Every element of the function's domain is the image of at most one element of its domain.</em>
First table:
No. Because for x = 12 and x = 14 we have the same value of y = 197
Second table:
No. Because for x = -2 and x = 2 we have the same value of y = 5
Third table:
No. Because for x = 7.25 and x = 8.5 we have the same value of y = 11
Answer:
Below is the procedure that was used to find the answer.
Step-by-step explanation:
Let be "e" the weight in pounds of the elephant and "c" the weight in pounds of the cat.
According to the information provided in the exercise, we know that The weight of an elephant is 
times the weight of a cat. Based on this we can write the following equation:
If the weight in pounds of the elephant is:
We must substitute this value into the equation and then solve for "c" in order to find the weight in pounds of the cat.
Then we get:
-3x-2.5=y would be an equivalent to that equation
