I am not sure about this but here goes nothing: d=2.5t+2.2 is very familiar to y=mx+b y=d m=2.5 x=t b=2.2 to find a new quasion we substitute d and t into place wich equals 1=2.5(0)+b simplification and you get b=1 so your answer is d=2.5t+1
Answer: B has greater spread than A.
Step-by-step explanation:
Since we have given that
Set A: {38, 12, 23, 48, 55, 16, 18}
Range of A = Highest - Lowest
Range of A = 55 - 12
Range of A = 43
Set B:{44, 13, 24, 12, 56}
Range of B = Highest - Lowest
Range of B = 56 - 12
Range of B = 44
Since Range of B is more than range of A.
Hence, B has greater spread than A.
The Pythagoras theorem states that
the sum of squares of the shorter sides (legs) of a right triangle equals the square of the third side.
A corollary from the same theorem helps us solve this problem:
If the sum of the squares of the shorter sides of a triangle is greater than the square of the third side, the included angle is acute. ..... (case 1)
Conversely, if the sum of the squares of the shorter sides of a triangle is less than the square of the third side, the triangle is obtuse. .....(case 2)
Here we have
6^2+10^2 = 36+100=136 <12^2=144
Therefore case 2 applies, and the triangle is obtuse.
Answer:
The herbicide has no impact on fish
Step-by-step explanation:
Experimental research includes to divide the concerned group 'fishes' here into 'treatment' & 'control' group, to study impact of a treatment. Hypothesis test the statistical significance of propositions. Null hypothesis signifies no impact, alternate hypothesis signifies impact.
Let averages enzyme level of treatment & control be Xt & Xc
- Null Hypothesis [H0] : Xt = Xc, or Xt - Xc = 0
- Alternate Hypothesis [H1] : Xt ≠ Xc, or Xt - Xc ≠ 0
If hypothesis test suggests that there is no significant difference between treatment & control group enzyme level, so we reject H0 & accept H1. It implies that the herbicide has no significant impact on fishes enzymes.
