Answer:
Explanation:
To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.
The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.
So, en the exposed example:
- J and K are autosomal genes
- J and K are separated by 60 M.U.
- 60 M.U. means that there is 60% of recombination.
Cross) J K / j k x j k / j k
Gametes) JK Parental jk, jk, jk, jk
jk Parental
Jk Recombinant
jK Recombinant
One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.
1 M.U. -------------- 1% recombination
60 M.U. ------------ 60% recombination
30% Jk + 30% jK
100 M.U. - 60 M.U. = 40 M.U.
40M.U.--------------40 % Parental (Not recombinant)
20% JK + 20% jk
Punnet Square) JK jk Jk jK
jk JK/jk jk/jk Jk/jk jK/jk
J K / j k = 20%
j k / j k = 20%
J k / j k = 30%
j K / j k = 30%
It helps them stay safe from predators
Answer: c. 0.15%
Explanation:
The blood alcohol concentration or BAC refers to the percentage of alcohol present in the bloodstream. The value of blood alcohol concentration of 0.15% is very high. It will affect the balance of voluntary muscles, walking and talking will also become difficult. The person will experience a severe increase in the rate of heart, the body temperature will rise, the person will experience irregular breathing and the bladder control will become weak.
Answer is stretch receptors.
Stretch receptors respond to the distention of muscle wall of the bladder and are neurologically linked to the medulla. Stretch receptors in the bladder signal the parasympathetic nervous system to stimulate muscarine receptors, present in the detrusor muscle, to make him contract. This leads to the expulsion of urine.
