answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
NNADVOKAT [17]
2 years ago
14

Water discharging into a 10-m-wide rectangular horizontal channel from a sluice gate is observed to have undergone a hydraulic j

ump. The flow depth and velocity before the jump are 0.8m and 7m/s, respectively. Determine (a) the flow depth and the Froude number after the jump (b) the head loss (c) the dissipation ratio.

Engineering
1 answer:
mezya [45]2 years ago
4 0

Answer:

A) flow depth after jump = 2.46 m,  Froude number after jump = 0.464

B) head loss = 0.572 m

C) dissipation ratio = 0.173

Explanation:

Given data :

width of channel = 10-m

velocity of before jump (V1) = 7 m/ s

flow depth before jump (y1) = 0.8 m

A) determining the flow depth and the Froude's number after the jump

attached below is the solution

B) head loss

HL = Y1 -Y2 + \frac{V_{1} ^2 - V_{2} ^2}{2g} = 0.8 - 2.46 + \frac{49 - 5.1984}{19.62} = 0.572

C) dissipation ratio

HL / Es1 = 0.572 / 3.3 = 0.173

Es1 = 0.8 + \frac{7^2}{2*9.81} = 0.173

You might be interested in
A solid steel shaft has to transmit 100 kW at 160 RPM. Taking allowable shear stress at 70 Mpa, find the suitable diameter of th
MA_775_DIABLO [31]

Answer:

The diameter of the shaft is 80.5 mm.

Explanation:

Torsion equation is applied for the diameter of the solid shaft.

Step1

Given:

Power of the shaft is 100 kw.

Revolution per minute is 160 RPM.

Allowable shear stress is 70 Mpa.

Maximum torque is 20% more than the mean torque.  

Step2

Mean torque is calculated as follows:

P=T\omega

P=T(\frac{2\pi N}{60})

100\times 1000=T(\frac{2\pi 160}{60})

T=5968.31 N-m

Step3

Maximum torque is calculated as follows:

T_{max}=(1+\frac{20}{100})T

T_{max}=1.2T

T_{max}=1.2\times 5968.31

T_{max}=7161.97 N-m

Step4

Apply torsional equation for diameter of shaft as follows:

\tau _{max}=\frac{T_{max}}{\frac{\pi d^{3}}{16}}

70\times 10^{6}=\frac{7161.97}{\frac{\pi d^{3}}{16}}

d^{3}=5.211\times 10^{-4}

d=0.0805 m

or,

d=80.5 mm

Thus, the diameter of the shaft is 80.5 mm.

7 0
2 years ago
Two airstreams are mixed steadily and adiabatically. The first stream enters at 35°C and 30 percent relative humidity at a rate
BartSMP [9]

Answer:

a)The specific humidity is _0.00881_kg H2O/kg dry air.

b)The relative humidity is _59.8_ %.

c)The dry-bulb temperature is _20.2_ °C.

d)The volume flow rate of the mixture is _39.77_m3/min

Explanation:

First let determine the enthalpy h1 and absolute humidity W1 from the psychometric chart using temperature T1 = 35°C and relative humidity Q1 = 30%

h1 = 62.2kJ/kg

V1 = 0.89m³/kg

W1 = 0.01054

The volume flow rate V'1 = 15m³/min, the mass flow rate m'1 is ,

m'1 = V'1/v1 = 15/0.89 = 16.85kg/min

Also, From temperature T2 = 12°C and relative humidity Q2 = 90% and volume flow rate V'2 = 25m³/min

h2 = 31.9kJ/kg

V2 = 0.82m³/kg

W2 = 0.00785

the mass flow rate m'2is ,

m'2 = V'2/v2 = 25/0.82 = 30.49kg/min

To get the absolute humidity W3 and the enthalpy h3,

m'1/m'2 = (W2-W3)/(W3-W1)

16.85/30.49 = (0.00785-W3)/(W3-0.01054)

0.5526(W3-0.01054) = (0.00785-W3)

0.5526W3 - 0.00582 = 0.00785-W3

0.5526W3 + W3 = 0.00785 + 0.00582

1.5526W3 = 0.01367

W3 = 0.01367/1.5526 = 0.00881

absolute humidity W3 = 0.00881

m'1/m'2 = (h2-h3)/(h3-h1)

16.85/30.49 = (31.9 - h3)/(h3 - 62.2)

0.5526(h3 - 62.2) = (31.9 - h3)

0.5526h3 - 34.37 = 31.9 - h3

0.5526h3 + h3 = 31.9 + 34.37

1.5526h3 = 66.27

h3 = 66.27/1.5526 = 42.68kJ/kg

enthalpy h3 = 42.68kJ/kg

Use W3 and h3 to determine temperature T3, relative humidity Q3 and and specific volume V3 all through psychometric chart

T3 = 20.2°C

Q3 = 59.8%

V3 = 0.84m³/kg

By last of mass conversations, we can determine m3,

m3 = m1 + m2

m3 = 16.85 + 30.49 = 47.34kg/min

Then, the volume flow rate V'3 can be found by,

V'3 = m3*V3

V'3 = 47.34*0.84 = 39.77m³/min.

volume flow rate V'3 = 39.77m³/min.

4 0
2 years ago
Q5. A hypothetical metal alloy has a grain diameter of 2.4 x 10-2 mm. After a heat treatment at 575°C for 500 min, the grain dia
alexdok [17]

Time is 244.89 minutes

<u>Explanation:</u>

<u />

Given:

Hypothetical diameter, d₀ = 2.4 X 10⁻² mm

Increase in diameter, d = 7.3 X 10⁻² mm

d₀ = 2.4 X 10⁻² mm

Time, t = 500 min

To solve K:

K = \frac{d^n - d_o^n}{t}

On substituting the value:

K = \frac{(7.3 X 10^-^2)^2^.^2 - (2.4 X 10^-^2)^2^.^2}{500} \\\\\\K = 5.8 X 10^-^6 mm^2^.^2/min

From the value of K, t can be calculated as:

t = \frac{d^2^.^2 - d_o^2^.^2}{K} \\\\t = \frac{(5.5 X 10^-^2)^2^.^2 - (2.4 X 10^-^2)^2^.^2}{5.8 X 10^-^6} \\\\t = 244.89 min

8 0
2 years ago
. Carly's Catering provides meals for parties and special events. In Chapter 2, you wrote an application that prompts the user f
klio [65]

Answer:

Explanation:

public class Event

  public final static int PRICE_PER_GUEST = 35;

  public final static int CUT_OFF = 50;

 

  //Attributes

  private String eventNum;

  private int noOfGuest;

  private int price;

 

  /**

  * param eventNum the eventNum to set

  */

  public void setEventNum(String eventNum)

      this.eventNum = eventNum;

 

 

  /**

  * param noOfGuest the noOfGuest to set

  */

  public void setNoOfGuest(int noOfGuest)

      this.noOfGuest = noOfGuest;

      this.price = this.noOfGuest * PRICE_PER_GUEST;

 

 

  /**

  * return the eventNum

  */

  public String getEventNum()

      return eventNum;

 

 

  /**

  * return the noOfGuest

  */

  public int getNoOfGuest()

6 0
2 years ago
A glass (k = 1.1 W/m.K) spherical tank is filled with chemicals undergoing exothermic reaction. The reaction keeps the inner sur
Alex Ar [27]

Answer:

We are getting the outer surface temperature as To=54.415°Cwhich is greater than 50°C. Thus, its not safe as it causes thermal burns.

Explanation:

The solution and complete explanation for the above question and mentioned conditions is given below in the attached document.i hope my explanation will help you in understanding this particular question.

7 0
2 years ago
Other questions:
  • Write a simple phonebook program that reads in a series of name-number pairs from the user (that is, name and number on one line
    12·1 answer
  • What can your employer do to protect you from overhead power lines?
    8·1 answer
  • Rough Riders Inc. manufactures jeans in the cutting and sewing process. Jeans are manufactured in 50-jean batch sizes. The cutti
    13·1 answer
  • 5 kg of steam contained within a piston-cylinder assembly undergoes an expansion from state 1, where the specific internal energ
    7·1 answer
  • Movies( title, year, length, genre, studioName, producerC#) StarsIn(movieTitle, movie Year, starName) MovieStar(name, address, g
    9·1 answer
  • g The function below takes a single string parameter: sentence. Complete the function to return everything but the middle 10 cha
    15·1 answer
  • 3. Consider a 10-m-long smooth rectangular tube, with a = 50 mm and b=25 mm, that is maintained at a constant surface temperatur
    5·1 answer
  • Which requirement is an appropriate reason for a business to use information technology (IT) tools
    9·1 answer
  • 4.116 The lid of a roof scuttle weighs 75 lb. It is hinged at corners A and B and maintained in the desired position by a rod CD
    9·1 answer
  • 5. Which of these materials in a shop contain metals and toxins and can pollute the environment? A) Antifreeze B) Solvents C) Ba
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!