Answer:
D. 1 BB : 2 Bb : 1 bb
Explanation:
This question involves a single gene coding for fur color in guinea pig. Black fur (B) is dominant over white fur (b). This means that, as stated in the question, if a black fur parent (BB) is crossed with a white fur parent (bb), a 100% heterozygous offspring (Bb) with black fur will result.
If two heterozygous guinea pigs are crossed i.e. Bb × Bb, the following gametes will be produced by each heterozygous parent:
Bb = B and b
Using these gametes in a punnet square (see attached image), offsprings with the following genotypic ratio will be produced:
1 BB : 2 Bb : 1 bb
BB and Bb = black fur guinea pigs
bb = white fur guinea pigs
Answer:
whats the full answer for b I think its your best bet
Answer:
All crosses and proportions, genotypes and phenotypes are attached.
Explanation:
a. Within living organisms, staining is a characteristic governed by a polygenic inheritance, which means that there is more than one gene involved in the staining process. as you already know, each gene has two alleles, if a trait is controlled by 2 genes, it means that we will have 4 alleles at the crosses.
From the description between dominance and recessivity between the alleles that control the colors of the pepper, shown in the question above, we can see that for the crossing between a red pepper and a green pepper, being able to generate a completely orange offspring, it would be necessary that the genotype of the parent peppers was: Red: RGRG, green: rgrg.
This would generate an orange-colored RrGg offspring, as you can see at the F1 crossing.
b. When individuals of F1 offspring are crossed, the combination of alleles and the determination of genotypes and phenotypes becomes much more complex, because instead of 4 alleles, we will have the combination of 16 alleles among themselves. Once again we will need to rely on the description of dominance and recessivity shown in the question above, so that from the crossing between the alleles of each gene, we can reach a conclusion, as you can see in the F2 crossing.
Answer: if i want to breed a rose and i don't have a certain kind of rose, i have to cross between them until i have a kind of rose that express the phenotype i was looking for. Once i've got it, i'll try to cross it with another rose and generate more species like that to cross with the rose that express the phenotype, this favors to generate a specie that have a pure phenotype.
Explanation: The answer is explain by the Mendel's laws.
Mendel's second law:
if you have two roses that are heterozygous and you cross them, their offspring have a 25% probability of generating a homozygous phenotype for a certain recessive characteristic (such as the rich smell of roses that is not a dominant character), 50% of generate heterozygotes with a dominant phenotype, and 25% generate other homozygotes with a dominant phenotype.
Once the offspring with the recessive homozygous character are obtained, it is possible to start making crosses between those of a recessive nature and there Mendel's first law applies
All the homozygous recessive individuals that are crossed will have a 100% homozygous recessive offspring.
Also, if you cross heterozygotes with another heterozygotes the offspring will be 100% heterozygotes
