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lisov135 [29]
2 years ago
12

Leslie was able to map \overline{ST} ST start overline, S, T, end overline onto \overline{QR} QR ​ start overline, Q, R, end ove

rline using a rotation and dilation. Leslie concluded: "I was able to map \overline{ST} ST start overline, S, T, end overline onto \overline{QR} QR ​ start overline, Q, R, end overline using a sequence of rigid transformations, so the figures are congruent." What error did Leslie make in her conclusion?
Mathematics
2 answers:
sladkih [1.3K]2 years ago
3 0

The fact that Leslie used a dilation is where she made the mistake. A dilation either shrinks or enlarges a figure. So it made segment ST either larger or smaller to be able to fit to segment QR.

But congruent segments are always the same length. So there's no way that a dilation can be involved. Only rigid transformations of translations (aka shifting), reflections, and rotations are allowed. A dilation is not a rigid transformation.

azamat2 years ago
3 0

Answer:

A

Step-by-step explanation:

took it on khan academy

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∆ABC is translated 2 units down and 1 unit to the left. Then it is rotated 90° clockwise about the origin to form ∆A′B′C′. The c
Ivenika [448]

Answer:

A'(-2, 1), B'(1, 0), C'(-1, 0)

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, dilation and translation.

If a point X(x, y) is translated a units right and b units down, the new location is X'(x + a, y + b) whereas if a point X(x, y) is translated a units left and b units up, the new location is X'(x - a, y - b).

If a point X(x, y) is rotated 90° clockwise about the origin, the new location is X'(y, -x)

From the image attached, ∆ABC is at A(0, 0), B(1,3) C(1, 1)

If ∆ABC is translated 2 units down and 1 unit to the left (x - 1, y - 2), the vertices would be A*(-1, -2), B*(0, 1), C*(0, -1)

If it is then rotated 90° clockwise about the origin, the new location is A'(-2, 1), B'(1, 0), C'(-1, 0)

7 0
2 years ago
Yolanda paid for her movie ticket using 28 coins, all nickels and quarters. The ticket cost $4. Which system of linear equations
VMariaS [17]
N + q = 28
0.05n + 0.25q = 4
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2 years ago
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Peter says that 3/4 of a pizza is always the same as 6/8 of a pizza. Nadia says that while they are equivalent fractions, 3/4 an
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6/8 is 3/4 and both is 75% of a pizza but, the eighths of a pizza is a smaller slice of pizza.

4/4 is four slices of pizza
8/8 is eight slices of pizza         They are different amounts.
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2 years ago
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A supermarket has two customers waiting to pay for their purchases at counter I and one customer waiting to pay at counter II. L
Pachacha [2.7K]

Answer:

b. 0.864

Step-by-step explanation:

Let's start defining the random variables.

Y1 : ''Number of customers who spend more than $50 on groceries at counter 1''

Y2 : ''Number of customers who spend more than $50 on groceries at counter 2''

If X is a binomial random variable, the probability function for X is :

P(X=x)=(nCx)p^{x}(1-p)^{n-x}

Where P(X=x) is the probability of the random variable X to assume the value x

nCx is the combinatorial number define as :

nCx=\frac{n!}{x!(n-x)!}

n is the number of independent Bernoulli experiments taking place

And p is the success probability.

In counter I :

Y1 ~ Bi (n,p)

Y1 ~ Bi(2,0.2)

P(Y1=y1)=(2Cy1)(0.2)^{y1}(0.8)^{2-y1}

With y1 ∈ {0,1,2}

And P( Y1 = y1 ) = 0 with y1 ∉ {0,1,2}

In counter II :

Y2 ~ Bi (n,p)

Y2 ~ Bi (1,0.3)

P(Y2=y2)=(1Cy2)(0.3)^{y2}(0.7)^{1-y2}

With y2 ∈ {0,1}

And P( Y2 = y2 ) = 0 with y2 ∉ {0,1}

(1Cy2) with y2 = 0 and y2 = 1 is equal to 1 so the probability function for Y2 is :

P(Y2=y2)=(0.3)^{y2}(0.7)^{1-y2}

Y1 and Y2 are independent so the joint probability distribution is the product of the Y1 probability function and the Y2 probability function.

P(Y1=y1,Y2=y2)=P(Y1=y1).P(Y2=y2)

P(Y1=y1,Y2=y2)=(2Cy1)(0.2)^{y1}(0.8)^{2-y1}(0.3)^{y2}(0.7)^{1-y2}

With y1 ∈ {0,1,2} and y2 ∈ {0,1}

P( Y1 = y1 , Y2 = y2) = 0 when y1 ∉ {0,1,2} or y2 ∉ {0,1}

b. Not more than one of three customers will spend more than $50 can mathematically be expressed as :

Y1 + Y2 \leq 1

Y1 + Y2\leq 1 when Y1 = 0 and Y2 = 0 , when Y1 = 1 and Y2 = 0 and finally when Y1 = 0 and Y2 = 1

To calculate P(Y1+Y2\leq 1) we must sume all the probabilities that satisfy the equation :

P(Y1+Y2\leq 1)=P(Y1=0,Y2=0)+P(Y1=1,Y2=0)+P(Y1=0,Y2=1)

P(Y1=0,Y2=0)=(2C0)(0.2)^{0}(0.8)^{2-0}(0.3)^{0}(0.7)^{1-0}=(0.8)^{2}(0.7)=0.448

P(Y1=1,Y2=0)=(2C1)(0.2)^{1}(0.8)^{2-1}(0.3)^{0}(0.7)^{1-0}=2(0.2)(0.8)(0.7)=0.224

P(Y1=0,Y2=1)=(2C0)(0.2)^{0}(0.8)^{2-0}(0.3)^{1}(0.7)^{1-1}=(0.8)^{2}(0.3)=0.192

P(Y1+Y2\leq 1)=0.448+0.224+0.192=0.864\\P(Y1+Y2\leq 1)=0.864

7 0
2 years ago
RQ is tangent to Circle S. Use the diagram below to find the measure of QRS. mQRS < 90 mQRS > 90 mQRS = 90 not enough info
Masteriza [31]
Given that you did not include the diagram showing the circle, the tangent line and the points Q, R, and S, I am going to give you the explanation to answer the question.

1) The tangent lines to a circle form a 90° angle with the radius at the point of intersection.

2) Therefore, if the point of intersection of the tangent line and the circle is named R, and the points S and Q are one the center of the circle and the other is on the line RQ, then you know that the segment SR is a radius and the line RQ is the tangent, which means that they are perpendicular, i.e. the angle QRS is measures 90°.

In this case the answer is m angle QRS = 90°.

3) Otherwise the angle is different to 90° and you need to observe the figure to conclude whether it is greater than 90°, less than 90° or there is not enough information.
7 0
2 years ago
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