Question:
Read the excerpt from Julius Caesar, act 1, scene 2.
CASSIUS: ‘Tis just; And it is very much lamented, Brutus, That you have no such mirrors as will turn Your hidden worthiness into your eye, That you might see your shadow. I have heard 5 Where many of the best respect in Rome– Except immortal Caesar‐speaking of Brutus, And groaning underneath this age’s yoke, Have wished that noble Brutus had his eyes.
BRUTUS: Into what dangers would you lead me, Cassius, 10 That you would have me seek into myself For that which is not in me?
CASSIUS: Therefore, good Brutus, be prepared to hear. And since you know you cannot see yourself So well as by reflection, I, your glass, 15 Will modestly discover to yourself That of yourself which you yet know not of.
Answer:
The correct choice is D)
Explanation:
Cassius speaks of Brutus as one who is unable to see or know his own value and presumes to help him therewith. He does this by pointing out that many of the well respected people in Rome wish that he were in Caesars shoes as King.
Cheers!
There could be extra tips or they could be taxed differently
5+ 4e = -7 is the correct answer.
Answer:
The answer is below
Step-by-step explanation:
A sugar refinery has three processing plants, all receiving raw sugar in bulk. The amount of raw sugar (in tons) that one plant can process in one day can be modelled using an exponential distribution with mean of 4 tons for each of three plants. If each plant operates independently,a.Find the probability that any given plant processes more than 5 tons of raw sugar on a given day.b.Find the probability that exactly two of the three plants process more than 5 tons of raw sugar on a given day.c.How much raw sugar should be stocked for the plant each day so that the chance of running out of the raw sugar is only 0.05?
Answer: The mean (μ) of the plants is 4 tons. The probability density function of an exponential distribution is given by:

a) P(x > 5) = 
b) Probability that exactly two of the three plants process more than 5 tons of raw sugar on a given day can be solved when considered as a binomial.
That is P(2 of the three plant use more than five tons) = C(3,2) × [P(x > 5)]² × (1-P(x > 5)) = 3(0.2865²)(1-0.2865) = 0.1757
c) Let b be the amount of raw sugar should be stocked for the plant each day.
P(x > a) = 
But P(x > a) = 0.05
Therefore:
![e^{-0.25a}=0.05\\ln[e^{-0.25a}]=ln(0.05)\\-0.25a=-2.9957\\a=11.98](https://tex.z-dn.net/?f=e%5E%7B-0.25a%7D%3D0.05%5C%5Cln%5Be%5E%7B-0.25a%7D%5D%3Dln%280.05%29%5C%5C-0.25a%3D-2.9957%5C%5Ca%3D11.98)
a ≅ 12
Sample: all available hanging baskets at one of the businesses in town that sells them
<span>Population: all available hanging baskets at the three businesses in town that sell them
I'm not 100% but its my best guess</span>