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Rama09 [41]
2 years ago
10

What is the control group in his experiment? The uncovered rows The covered rows The other 7 fields There is no control group

Biology
1 answer:
Natasha_Volkova [10]2 years ago
7 0
In a experiment , then u
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True or False. The more threads a screw has the greater the holding power of the screw.
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Where would you expect to find the simplest body<br> plans?
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Most sponge body plans are slight variations on a simple tube-within-a-tube design. which of the following is a key limitation of sponge body plans? sponges lack the specialized cell types needed to produce more complex body plans. the reliance on osmosis/diffusion requires a design that maximizes the surface area to volume ratio of the sponge. choanocytes must be protected from the hostile exterior environment. spongin cannot support heavy bodies.
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What best explains the interaction between tRNA and mRNA during translation?
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a hiker has become overwhelmed with heat while walking in the grand canyon. the hiker's body goes into overdrive to keep cool in
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2 years ago
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One polled (hornless) bull is bred to 3 cows. With Cow A, which is horned, a polled calf is produced. With Cow B, also horned, a
Arisa [49]

Answer:

Bull = Pp

Cow A = pp

Cow B = pp

Cow C = Pp

Explanation:

In cows polled (P) is dominant over horned (p) trait.

The bull is polled so it can be PP or Pp. Cow B is horned so it must be pp. Resultant offspring from bull X Cow B is also a horned calf (pp). This calf must have received one p from the bull. So the bull's genotype is Pp.

Cow A is also a horned cow so it must be pp. When bull X Cow A, a polled calf is produced. Since the bull's genotype is Pp and Cow A's genotype is pp, this polled calf will be Pp like the bull.

Cow C is polled like the bull so it can be PP or Pp. However on crossing with the bull (Pp) a horned calf is produced (pp). This calf got one p allele from the bull and p allele from the Cow C. So Cow C's genotype must be Pp.

Hence,

Bull = Pp

Cow A = pp

Cow B = pp

Cow C = Pp

5 0
2 years ago
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