Question

A computer has 38 address lines. How many locations in Mega bytes can it address?

Answer 1

Answer:

The computer can address 34359,738368 megabytes

Explanation:

Given

Address Lines (n) = 38

Required

Determine the number of location it can address

Number of addressable locations (N) in bits is calculated as thus

$N = 2^n.$

Substitute 38 for n

$N = 2^{38}$

$N = 274877906944\ bits$

Next; is to convert from bits to megabytes

Start by converting to bytes

1 bit = 0.125 bytes;

So;

$N = 274877906944 * 0.125\ bytes$

$N = 34359738368\ bytes$

Convert from byte to megabyte

$1\ byte = 10^{-6}\ megabyte$

So;

$N = 34359738368\ * 10^{-6}\ MB$

$N = 34359,738368\ MB$

Hence, the computer can address 34359,738368 megabytes