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luda_lava [24]
2 years ago
4

A set of three scores consists of the values 3, 7, and 2. Σ2X-2 = 22 E(x-1)2 = -41 Hint: Remember to follow the order of mathema

tical operations.
Mathematics
1 answer:
Ronch [10]2 years ago
7 0

Answer:

Step-by-step explanation:

Given the following scores 3, 7 and 2, we are to find the expression Σ2X-2 and Σ(X-1)²

The value of X's are 3, 7 and 2. Substituting the values we will have;

Σ2X-2 = [2(3)+2(7)+2(2)] - 2

Σ2X-2 = (6+14+4) - 2

Σ2X-2  = 24-2

Σ2X-2  = 22

For  Σ(X-1)²

Σ(X-1)² = (3-1)²+ (7-1)² + (2-1)²

Σ(X-1)² = 2²+6²+1²

Σ(X-1)² = 4+ 36+1

Σ(X-1)² = 41

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5 ft

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If p is a polynomial show that lim x→ap(x)=p(a
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Let p(x) be a polynomial, and suppose that a is any real number. Prove that

lim x→a p(x) = p(a) .

 

Solution. Notice that

 

2(−1)4 − 3(−1)3 − 4(−1)2 − (−1) − 1 = 1 .

 

So x − (−1) must divide 2x^4 − 3x^3 − 4x^2 − x − 2. Do polynomial long division to get 2x^4 − 3x^3 − 4x^2 – x – 2 / (x − (−1)) = 2x^3 − 5x^2 + x – 2.

 

Let ε > 0. Set δ = min{ ε/40 , 1}. Let x be a real number such that 0 < |x−(−1)| < δ. Then |x + 1| < ε/40 . Also, |x + 1| < 1, so −2 < x < 0. In particular |x| < 2. So

 

|2x^3 − 5x^2 + x − 2| ≤ |2x^3 | + | − 5x^2 | + |x| + | − 2|

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Thus, |2x^4 − 3x^3 − 4x^2 − x − 2| = |x + 1| · |2x^3 − 5x^2 + x − 2| < ε/40 · 40 = ε.

3 0
2 years ago
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