Answer:
cubic function
Step-by-step explanation:
y = x³ is a cubic function ( cube relating to the exponent 3 )
It can also be called a degree 3 function
Answer:
y=3x^2 is the quadratic that presents the table
x | 0 1 2 3
y | 0 3 12 27
The exponential that includes (1,4) takes off a bit faster than the others near x=0.
Step-by-step explanation:
If the table is:
x | 0 1 2 3
y | 0 3 12 27
It says it is a quadratic and we know the y-intercept is 0 since we have the point (0,0).
y=ax^2+bx
Now we need to use 2 more mores and we should wind up with a system to solve for a and b.
(1,3) (2,12)
3=a(1)^2+b(1) 12=a(2)^2+b(2)
3=a+b 12=4a+2b
6=2a+b (divided both sides by 2)
So we are solving the system
3=a+b
6=2a+b
-------------- I'm going to choose elmination because it is already setup that way. I'm going to subtract the equations. In doing so, the b's will cancel.
3-6=a-2a
-3=-a
a=3
so since 3=a+b and a=3 then b=0
So the quadratic is y=3x^2
And perhaps we could have looked for an easier way to solve this since we winded up with such a simple quadratic. I'm saying it might have been just easier looking for a pattern but something it won't be that easy.
Answer:
The value of x is 
hours.
Step-by-step explanation:
Machine A = 5 hours
Machine B = x hours
Machine A and B = 2 hours
Using the formula: 
where:
T is the time spend by both machine
A is the time spend by machine A
B is the time spend by machine B
Let multiply the entire problem by the common denominator (5B)
2x + 10 = 5x
Collect the like terms
10 = 5x - 2x
10 = 3x
3x = 10
Divide both side by the coefficient of x (3)
hours.
Therefore, Machine B will fill the same lot in hours.
EFG ~ LMN, if EF ~ LM, then whatever the number is for EF times whatever the others are multiplied by, you will get LM
for example:
FG (10) ~ MN (20)
if EF is (5), then LM is (10) (for you are multiplying by two.
Another example:
if FG is (100) ~ MN will be (200) (again for you are multiplying by two.
hope this helps
