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Ivahew [28]
2 years ago
14

construct a triangle ABC in which AB is 6 CM , BC is 4.5 cm and AC is 5.9 cm also construct a perpendicular bisector of sides AB

and BC​
Mathematics
1 answer:
Vaselesa [24]2 years ago
3 0

step by step explanation:

Draw a perpendicular line AB=6cm

Open your compass to a radius of 4.5cm and place it on B to construct an arc

Again open your compass to a radius of 5.9cm and step at A and draw an arc to intersect the first one at C

Open your compass to a reasonable radius and step at A and B to construct an arc

With the same radius step at B and C to construct another arc

Draw a line to bisect the arcs

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The Chang's neighbor owns a ready-mix company. The company receives an order for 12.5 cubic yards of concrete. This mixture of c
ella [17]
The quantities in the proportion you give add to 16 pounds, of which 2 pounds are cement. That is, cement constitutes 1/8 of the total weight.

For each yard of concrete, 4000 lb/8 = 500 lb of cement are used.

For 12.5 yards of concrete, 12.5 * 500 = 6,250 pounds of cement will be used.

_____
"yard" in this case is shorthand for "cubic yard".
3 0
2 years ago
Henry works at a warehouse where he earns $23.56 per hour. How much money will Henry earn after working for 37 hours and 42 minu
Burka [1]

Answer:

$888.21

Step-by-step explanation:

We'll break this problem into two chunks.

First, find the number of dollars Henry gets after working for 37 hours. Since he gets paid $23.56 per hour, all you do is multiply how many hours he's worked (37) by the rate he gets paid (23.56) which gets you $871.72.

Second, adding 42 minutes onto the 37 hours. Since there are 60 minutes in one hour, all you have to do is divide 42 minutes by 60 minutes to get how much of 42 minutes is 1 hour, which is 0.7. Multiply 0.7 by 23.56 (the rate he gets paid per hour) and you have $16.49.

Adding the two sums gets you 888.21 dollars in total.

8 0
2 years ago
The quality control team of a company checked 800 digital cameras for defects. The team found that 20 cameras had lens defects,
dmitriy555 [2]

Answer:

0.025

Step-by-step explanation:

-This is a conditional probability problem.

-Let L denote lens defect and C charging defect.

#We first calculate the probability of a camera having a lens defect;

P(lens)=\frac{Lens}{Total}\\\\=\frac{20}{800}\\\\=0.025

#Calculate the probability of a camera having a charging defect:

P(Charging)=\frac{Charging}{Total}\\\\=\frac{25}{800}\\\\=0.03125

The  the probability that a camera has a lens defect given that it has a charging defect is calculated as:

P(L|C)=\frac{P(C)P(L)}{P(C)}\\\\=\frac{0.025\times 0.03125}{0.03125}\\\\=0.025

Hence,  the probability that a camera has a lens defect given that it has a charging defect is 0.025

6 0
2 years ago
7+6x14-9=37 insert parentheses
d1i1m1o1n [39]

Answer:

7+6\times(14-9)=37

Step-by-step explanation:

The given expression is

7+6\times14-9

If we evaluate the expression as it is  we will get;

7+84-9=82

But we want to insert parenthesis so that we will use PEDMAS to obtain 37 as the result.

The only way this can be achieved is when we insert the parenthesis as shown below;

7+6\times(14-9)=7+6(5)=7+30=37

4 0
2 years ago
Data from 14 cities were combined for a​ 20-year period, and the total 280 ​city-years included a total of 107 homicides. After
leonid [27]

Answer:

P(0) =  0.6825

P(1) = 0.2607

Step-by-step explanation:

From the given information, the number of homicide is 107 and the total number of homicides per city –year is 280.

Let us denote the number of homicides per city-year as X.

The mean value, X is calculated as:

\begin{array}{c}\\{\rm{Mean}} = \frac{{107}}{{280}}\\\\ = 0.382\\\end{array}  

Mean=   107/280 = 0.382  

The mean number of homicides per city- year \left( {\lambda = \mu } \right)(λ=μ) is 0.382.

a. The probability that zero homicides is obtained is as below:

\begin{array}{c}\\P\left( {X = 0} \right) = \frac{{{e^{ -0.382}}{{\left( {0.382} \right)}^0}}}{{0!}}\\\\ = \frac{{\left( {0.6825 \right)\left( {\rm{1}} \right)}}{1}\\\\ = 0.6825\\\end{array}  

P(X=0) =  e  −0.382  (0.382)⁰​/1  

= (0.6825)(1) /1  

P(X=0) = 0.6825

Thus, the probability that zero homicides P(0) is 0.6825.

b. The probability that one homicides is obtained is as below:

\begin{array}{c}\\P\left( {X = 0} \right) = \frac{{{e^{ -0.382}}{{\left( {0.382} \right)}^0}}}{{0!}}\\\\ = \frac{{\left( {0.6825 \right)\left( {\rm{1}} \right)}}{1}\\\\ = 0.6825\\\end{array}  

P(X=1) =  e  −0.382  (0.382)¹​/1  

= (0.6825)(0.382)/1  

P(X=1) = 0.2607

Thus, the probability that zero homicides P(0) is 0.2607.

​

5 0
2 years ago
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