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2 years ago

Hugo and Koby are measuring the heights of plants in biology class.

Mathematics

2 answers:

Verizon [17]2 years ago

3 0

The answers are shorter, higher, 2cm, 15cm, 20% and 15%.

Step-by-step explanation:

Step 1; From the given data Hugo measured his plant higher than its original height. Hugo measured his plant as 12 cm while it was actually 10 cm. So Hugo's measurement was off by 2cm. Hugo's percent error is given by dividing the difference in values by the actual value.= multiplied by 100.

% error = (difference in values / actual value) × 100

Hugo's % error = (12 - 10)/ 10 × 100 = 2/10 × 100 = 20%.

Step 2; Koby measured his plant lower than his plant's original height. He measured it to be 85 cm while it was 100 cm tall. So Koby's measurement was off by 15cm. The percent error is calculated in the same way.

% error = (difference in values / actual value) × 100

Koby's % error = (100 - 85)/ 100 × 100 = 15/100 × 100 = 15%.

Step 3; Hugo had a percent error of 20% while Koby has a percent error of 15%. So Hugo had a higher percent error of the two.

fredd [130]2 years ago

3 0

Answer:

Step-by-step explanation:

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In a survey of 447 registered voters, 157 of them wished to see Mayor Waffleskate lose her next election. The Waffleskate campai

Hitman42 [59]

<h2>Answer with explanation:</h2>

Let p be the true proportion of registered voters wish to see Mayor Waffleskate defeated.

As per given , we have

$H_0: p\leq0.27\\\\ H_a: p >0.27$

Sample size : n= 447

Number of of registered voters wish to see Mayor Waffleskate defeated = 157

I.e. sample proportion : $\hat{p}=\dfrac{157}{447}\approx0.3512$

Confidence interval for population proportion is given by :-

$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where n= sample size

$\hat{p}$ = sample proportion

z* = critical z-value.

Critical z-value for 98% confidence interval is 2.33. (By z-table)

Then, the 98% confidence interval for the proportion of registered voters who wish to see Waffleskate defeated will be :

$0.3512\pm2.33\sqrt{\dfrac{0.3512(1-0.3512)}{447}}\\\\=0.3512\pm (2.33)(0.022577656)\\\\=0.3512\pm 0.05260593848\\\\=(0.3512-0.05260593848,\ 0.3512+0.05260593848)\\\\=(0.29859406152,\ 0.40380593848)\approx(0.299,\ 0.404)$

Since the 0.27 < 0.299 , it means 0.27 does not belong to the above confidence interval.

So , we reject the null hypothesis ( $H_0$ ).

So , <u>98% confidence interval does not support the claim.</u>

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2 years ago

Cells B1, C1, and D1 contain the values Seat1Row1, Seat1Row2, and Seat1Row3. If cells B1, C1, and D1 were selected, and autofill

Reil [10]

Answer:

The autofilled values would be Seat1Row4, Seat1Row5, Seat1Row6

Step-by-step explanation:

Given

B1 = Seat1Row1

C1 = Seat1Row2

D1 = Seat1Row3

Required

Values of E1, F1, G1 if autofilled

Autofill in Microsoft Office Excel (Ms Excel).is used to automatically fill cells base on suggestion from previous cells.

The autofill feature of Ms Excel works data types such as numbers and alphanumeric among others.

But for autofill to work on alphanumeric in Ms Excel, only the numeric part will be altered.

In this case, the series of text in B1, C1 and D1 are Seat1Row1, Seat1Row2, Seat1Row3

"Seat1Row" will be regarded as string while 1,2,3 will be incremented and the resulting alphanumeric values will be saved in their respective cells.

Hence,

Cell E1 will be filled with Seat1Row4

F1 will be filled with Seat1Row5

G1 will be filled with Seat1Row6

See attachment

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2 years ago

Read 2 more answers

Is 8456 mL greater than 9L

Bond [772]

There are 1000 mL in one L. So, 9L = 9000mL. Therefore, no

Hope this helps!

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2 years ago

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Find the 6th term of the arithmetic sequence -4, 0, 4, 8,

bezimeni [28]

Answer:

Step-by-step explanation:

-4,0,4,8,12,16

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2 years ago

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Pleasantburg has a population growth model of P(t)=at2+bt+P0 where P0 is the initial population. Suppose that the future populat

yulyashka [42]

Answer:

The population will reach 34,200 in February of 2146.

Step-by-step explanation:

Population in t years after 2012 is given by:

$P(t) = 0.8t^{2} + 6t + 19000$

In what month and year will the population reach 34,200?

We have to find t for which P(t) = 34200. So

$P(t) = 0.8t^{2} + 6t + 19000$

$0.8t^{2} + 6t + 19000 = 34200$

$0.8t^{2} + 6t - 15200 = 0$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$0.8t^{2} + 6t - 15200 = 0$

So $a = 0.8, b = 6, c = -15200$

Then

$\bigtriangleup = 6^{2} - 4*0.8*(-15100) = 48356$

$t_{1} = \frac{-6 + \sqrt{48356}}{2*0.8} = 134.14$

$t_{2} = \frac{-6 - \sqrt{48356}}{2*0.8} = -141.64$

We only take the positive value.

134 years after 2012.

.14 of an year is 0.14*365 = 51.1. The 51st day of a year happens in February.

So the population will reach 34,200 in February of 2146.

6 0

2 years ago