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2 years ago

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A group of 444 friends likes to golf together, and each friend keeps track of her all-time lowest score in a single round. Their

low scores are all between 909090 and 100100100, except for Angie, whose low score is 808080. Angie then golfs a great round and has a new low score of 757575. How will decreasing Angie's low score affect the mean and median?

2 answers:

matrenka [14]2 years ago

8 0

Kcsjskskfnfjdnxnxkskgntjxmzmxsks UR DUMB HAHAHAHAHAHAAH

OLEGan [10]2 years ago

7 0

The answer is 892929 devise by 56 and u will get 1028 to my calendar u tryanna play Fortnite add me epic it’s QeezyOnYT I have all the skin in the game and 3000 vubucks

You might be interested in

which of the following is equivalent to 3 sqrt 32x^3y^6 / 3 sqrt 2x^9y^2 where x is greater than or equal to 0 and y is greater

Nutka1998 [239]

Answer:

$\frac{\sqrt[3]{16y^4}}{x^2}$

Step-by-step explanation:

The options are missing; However, I'll simplify the given expression.

Given

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$

Required

Write Equivalent Expression

To solve this expression, we'll make use of laws of indices throughout.

From laws of indices $\sqrt[n]{a} = a^{\frac{1}{n}}$

So,

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$ gives

$\frac{(32x^3y^6)^{\frac{1}{3}}}{(2x^9y^2)^\frac{1}{3}}$

Also from laws of indices

$(ab)^n = a^nb^n$

So, the above expression can be further simplified to

$\frac{(32^\frac{1}{3}x^{3*\frac{1}{3}}y^{6*\frac{1}{3}})}{(2^\frac{1}{3}x^{9*\frac{1}{3}}y^{2*\frac{1}{3}})}$

Multiply the exponents gives

$\frac{(32^\frac{1}{3}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

Substitute $2^5$ for 32

$\frac{(2^{5*\frac{1}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

$\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

From laws of indices

$\frac{a^m}{a^n} = a^{m-n}$

This law can be applied to the expression above;

$\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$ becomes

$2^{\frac{5}{3}-\frac{1}{3}}x^{1-3}*y^{2-\frac{2}{3}}$

Solve exponents

$2^{\frac{5-1}{3}}*x^{-2}*y^{\frac{6-2}{3}}$

$2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}$

From laws of indices,

$a^{-n} = \frac{1}{a^n}$ ; So,

$2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}$ gives

$\frac{2^{\frac{4}{3}}*y^{\frac{4}{3}}}{x^2}$

The expression at the numerator can be combined to give

$\frac{(2y)^{\frac{4}{3}}}{x^2}$

Lastly, From laws of indices,

$a^{\frac{m}{n} = \sqrt[n]{a^m}$ ; So,

$\frac{(2y)^{\frac{4}{3}}}{x^2}$ becomes

$\frac{\sqrt[3]{(2y)}^{4}}{x^2}$

$\frac{\sqrt[3]{16y^4}}{x^2}$

Hence,

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$ is equivalent to $\frac{\sqrt[3]{16y^4}}{x^2}$

8 0

2 years ago

According to an informal poll in Glenview 1/3

Talja [164]

Answer:

Percent form: 41.65%

Fraction form: $\frac{833}{2000}$

Step-by-step explanation:

33% of men support John Smith.

67% of women support John Smith.

Lets say, for instance, that there are 20 polled individuals -- 10 women and 10 men.

However, since 1.5 times as many men voted as women, we have to apply our poll to 15 men and 5 women.

33% of the 15 men makes 5 men who voted for Smith and 10 who did not.

67% of the 5 women makes 3.33 women who voted for Smith and 1.67 who did not.

Add these numbers together.

8.33 total voters were cast for John Smith, while 11.67 were not.

Now, divide 8.33 by 20 and multiply by 100 to obtain a percentage.

$\frac{8.33}{20} \\.4165\\41.65$

41.65% of voters voted for John Smith according to the results of the poll.

7 0

2 years ago

In a survey of a town, 56% of residents own a car, 21% of residents now a truck, and 4% of residents own both a car and a truck.

Vesna [10]

The conditional probability is 80

4 0

2 years ago

Based on the Fundamental Theorem of Algebra, how many complex roots does each of the following equations have? Write your answer

mars1129 [50]

Answer:

2, 2, 4, 6, 4

Step-by-step explanation:

Fundamental Theorem of Algebra states that 'An 'n' degree polynomial will have n number of real roots'.

1. The polynomial is given by $x(x^2-4)(x^2+16) = 0$

So, on simplifying we get that, $x(x+2)(x-2)(x^2+16)=0$ .

Since, degree of polynomial is 5, it will have 5 roots.

This gives us that the roots of the equation are x = 0, -2, 2, 4i and -4i

So, the number of complex roots are 2.

2. The polynomial is given by $(x^2+4)(x+5)^2 = 0$

Since, degree of polynomial is 4, it will have 4 roots.

Equating them both by zero, $(x^2+4)= 0$ and $(x+5)^2=0$ gives that the roots of the polynomial are x = 2i, -2i, -5, -5.

So, the number of complex roots are 2.

3. The polynomial is given by $x^6-4x^5-24x^2+10x-3=0$

Since, degree of polynomial is 6, it will have 6 roots.

On simplifying, we get that the real roots of the polynomial are x = -1.75 and x = 4.28.

So, the number of complex roots are 6-2 = 4.

4. The polynomial is given by $x^7+128=0$

Since, degree of polynomial is 7, it will have 7 roots.

On simplifying, we get that the only real root of the polynomial is x = -2.

So, the number of complex roots are 7-1 = 6.

5. The polynomial is given by $(x^3+9)(x^2-4)=0$

Since, degree of polynomial is 5, it will have 5 roots.

Simplifying the equation gives $(x+2)(x-2)(x+\sqrt[3]{9})(x^2-\sqrt[3]{9x}+9^{\frac{2}{3}})=0$

Equating each to 0, we get the real roots of the polynomial is $x=-3^{\frac{2}{3}}$

So, the number of complex roots are 5-1 = 4

6 0

2 years ago

Read 2 more answers

Katie has 4 grape candies and 3 cherry candies. The ratio of the mumber of grape candies to the total number of candies is what?

dimaraw [331]

Answer 4:7

Step-by-step explanation:

6 0

1 year ago

Read 2 more answers