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Lena [83]
2 years ago
11

In a rigid transformation on A ABC, AA'=BB' CC' and AA|BB|| CC. Which of the following transformations was applied to AABC?

Mathematics
1 answer:
zimovet [89]2 years ago
3 0

Answer:

Step-by-step explanation: What did you get for this lol I can’t figure it out and it’s on my quiz right now

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mrs sogiba is catering for her sons birthday party. she has invited some of her sons friends to the party. the number of friends
Alex
The only ones that would work are if the factor is composite and if 1 is added to it it can be divided into 48. So 15 would work. The factor 15 is composite, and if 1 is added it can be divided into 48.Therefore the son is 15.
7 0
2 years ago
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A sales representative can take one of 3 different routes from City Upper B to City Upper D and any one of 6 different routes fr
grigory [225]

Answer:

7

Step-by-step explanation:

7 0
2 years ago
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Given: line AB is congruent to line CD and line AD is congruent to line BC. Prove: angle D is congruent to angle B
Taya2010 [7]
AD = BC ----> Parallel lines
AC = AC -----> Reflexive property
<A = <C -----> Congruent angles
<D = <B -----> Congruent angles
8 0
2 years ago
Fernando evaluated the expression below. StartFraction 5 (9 minus 5) over 2 EndFraction + (negative 2) (negative 5) + (negative
Rzqust [24]

Answer:

Fernando incorrectly found the product of –2 and –5.

Step-by-step explanation:

Fernando evaluated the numerator of the fraction incorrectly.

Fernando simplified StartFraction 20 over 2 EndFraction incorrectly.

Fernando incorrectly found the product of –2 and –5.

Fernando evaluated (negative 3) squared incorrectly.

Fernando's calculation

5(9-5) / 2 + (-2)(-5) + (-3)^2

= 5(4) / 2 - 10 + 9

= 20/2 - 10 + 9

= 10 - 10 + 9

= 9

Correct calculation

5(9-5) / 2 + (-2)(-5) + (-3)^2

= 5(4) / 2 + (10) + 9

= 20/2 + 10 + 9

= 10 + 10 + 9

= 29

Therefore,

Fernando's error was multiplying (-2)(-5) to be equal to -10 instead of 10

Fernando incorrectly found the product of –2 and –5.

5 0
2 years ago
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A commuter railway has 800 passengers a day and charges each one 2 dollars. ?
Fiesta28 [93]

Answer:

I= -20p^2 + 840p

Step-by-step explanation:

When the ticket price is $2 there are 800 passengers daily, but every $0.1 increase in ticket price the number of passengers will be decreased by 2.  

You can put information into these equations of:

passenger- = (800-2x)

ticket price= p = $2 + 0.1x

Income is calculated by multiplying the number of the passenger with the ticket price. The answer will be expressed in terms of the ticket price, so we need to remove x from the passenger equation.

p= $2 +0.1x

p-$2 = 0.1x

x= 10p- $20

If  p= ticket price, the function for the number of passengers it will be:

passenger = (800-2x)

passenger = 800- 2(10p- $20)

passenger =800- 20p+40

passenger =840- 20p

The function of I will be:

I= passenger x ticket price

I=  840- 20p * p

I= -20p^2 + 840p

4 0
2 years ago
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