A
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is most likely the answer
The omnivorous flock will eat the most as it eats both insects and seeds. With the removal of fruit it will not be affected much.
The herbivorous flock will eat the least as it has the option to eat seeds only after the removal of fruit.
Explanation:
Let us take the example of Finches. Finches have many different species with different variations adaptable to conditions favorable as per availability of the type of food.
Lets say -
Species X and Y is provided with insects, seeds and fruit.
Species X - Omnivorous
Species Y - Herbivorous
The species X will be able to eat the most as it is an Omnivore.
The omnivorous flock will eat the most as it eats both insects and seeds. With the removal of fruit it will not be affected much.
Species Y will be able to eat the least as it is an herbivore.
The herbivorous flock will eat the least as it has the option to eat seeds only after the removal of fruit.
I feel like it could possibly be mobilism for like energy thats another word for energy
That's because they are in the same climate zone. The earth's climate zones change going from the north pole to the equator, and then from the equator to Antarctica, like a mirror image. The two are found in the same zones on the opposite hemispheres.
Answer:
The best answer to the question, given the research found on this particular process in E. Coli specifically, would be: D) It identifies hemimethylated base pairs and methylates the unmodified base.
Explanation:
According to research on this pretty complicated topic, in E. Coli specifically, and other gram negative prokaryotes, it has been found that the presence, or absence of methylation will initiate MutS, which is a protein both in prokaryotes and eukaryotes responsible, in a full complex, of initiating and carrying out the full mechanism of DNA mismatch repair. As the daughter DNA strands are produced from parent strands, these first ones arise with several deletions and mismatches which need to be repaired and they are recognized due to the fact that daughter strands are hemimethylated. This circumstance activates MutS in E. Coli, who will then bind to the DNA strand that needs to be repaired and together with other members of the complex, like MutH and MutL, begin the process of repair.
In eukaryotes and other prokaryotes, the exact process by which DNA is repaired by MutS is still not totally known.
