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Morgarella [4.7K]
2 years ago
14

Biologists studying wildlife in the state parks want to estimate the average weight of chipmunks. They measured the weights of 5

chipmunks from each of 10 parks. The mean of the data was 91 grams, and the median was 87 grams. Which predictions match the data?
Mathematics
2 answers:
kipiarov [429]2 years ago
7 0

Answer:

A and D

Step-by-step explanation:

Biologists studying wildlife in the state parks want to estimate the average weight of chipmunks.

They gave you both the question and the answer. Average is the same thing as mean so 91 would be the correct answer

egoroff_w [7]2 years ago
3 0

Answer:

Biologists studying wildlife in the state parks want to estimate the <em><u>average </u></em>weight of chipmunks.

They gave you both the question and the answer. Average is the same thing as mean so 91 would be the correct answer

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The sum of the interior angles of a polygon is
Crank

Answer:

D) 15

Step-by-step explanation:

The sum of the interior angles of a polygon is given by

(n - 2) \times 180

We have that, the sum of the interior angles of a polygon is

26 right angles. We want to find n, the number of sides.

We substitute into the formula to get:

(n - 2) \times 180 = 26 \times 90

Divide through by 90

2(n - 2) = 26

Divide through by 2

n - 2 = 13

n = 13 + 2

n = 15

6 0
2 years ago
A doctor orders 250 mg of Rocephin to be taken by a 19.8 Ib infant every 8 hours. The medication label shows that 75-150 mg/kg p
navik [9.2K]

Answer: Yes, doctor's order is within the desired range.


Step-by-step explanation:

We need to first convert 19.8 lb to kg.

We know that 1 kg=2.20 lb

Therefore, the weight of infant=19.8\div 2.2=9\ kg

Minimum Desired Dosage)=9\times75=675\ mg

Maximum Desired Dosage  =9\times150=1350\ mg

Since there are 24 hours in one day and the medication is ordered every 8 hours.

\\\Rightarrow24\div8= 3 times per day doctor ordered medication .

Total amount of Rocephin in a day=3\times250=750 mg ordered per day

And 750 mg is within the desired range of 675-1,350 mg

So, yes doctor has ordered a dosage within the desired range.

7 0
2 years ago
An animal shelter is feeding 24 dogs. Each dog is fed 8 ounces of dog food twice a day. How many pounds of dog food does the she
Brut [27]

there are 24 dogs, each one gets 8oz of dog food twice a day, so for 1 day only that'd be 16 oz, for 7 days for 1 dog only that'd be 16+16+16+16+16+16+16 oz or 112oz, just for 1 dog alone for 7 days(week).

now, there are 24 dogs, each one gets 112oz every week, 24 * 112 ounces.

8 0
2 years ago
Caitlin had used more thank 2 pounds of clay to make a jar? Would the amount remaining have been more or less than your answer t
11111nata11111 [884]
You do not make any sense. can you restate your question please

4 0
2 years ago
A study of immunizations among school‑age children in California found that some areas had rates of unvaccinated school‑age chil
Rom4ik [11]

Answer:

Probability that none of the 20 children in such a classroom would be unvaccinated is 0.055.

Step-by-step explanation:

We are given that a classroom of 20 children in one such area where 13.5% of children are unvaccinated.

If there are no siblings in the classroom, we are willing to consider the vaccination status of the 2020 unrelated children to be independent.

The above situation can be represented through binomial distribution;

P(X=r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,......

where, n = number of trials (samples) taken = 20 children

            r = number of success = none of the 20 children

            p = probability of success which in our case is probability that

                   children are unvaccinated, i.e; p = 13.5%

<u><em>Let X = Number of children that are unvaccinated</em></u>

So, X ~ Binom(n = 20, p = 0.135)

Now, Probability that none of the 20 children in such a classroom would be unvaccinated is given by = P(X = 0)

           P(X = 0)  =  \binom{20}{0} \times 0.135^{0} \times (1-0.135)^{20-0}

                          =  1\times 1 \times 0.865^{20}

                          =  0.055

<em>Hence, the probability that none of the 20 children in such a classroom would be unvaccinated is 0.055.</em>

8 0
2 years ago
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