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2 years ago

Which expression has the same value as tan(-45°)?

Mathematics

1 answer:

vitfil [10]2 years ago

8 0

Answer:

I think it's cot(135°)

Step-by-step explanation:

Cot 135° = Cot (π/2 + 45)

and,

Cot (π/2+45)= -tan (45),

because when a trigonometric ratio is impressed by using π/2 the ratio should be changed its opposite like sin value turns into a cos value, tan value turns into cot and vise versa. Then as 135° is in the second sector that means π/2<135°<π. So it should be -tan(45°)

As tan-45°= -tan 45° i think the answer is second one aka cot(135°)

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Sid need 0.6 meters of canvas material to make a carry-all bag for his wheelchair.if canvas is $10.09 per meter, how much will s

Olegator [25]

$6.05 because 10.09 × 0.6 is 6.054, round down because the last number is less than 5, and you have 6.05.

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2 years ago

A rectangular safe can hold 5184 cubic inches. Gold bars that are 3 inches by 6 inches by 2 inches fit to completely fill the sa

S_A_V [24]

Answer:

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Step-by-step explanation:

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2 years ago

Jada is making lasagna and pizzas for a party recipe calls for 1 1/4 cups and she uses 1/2 she doubled her recipe and made 5 piz

grigory [225]

This question is not correctly written

Complete Question

Jada is making lasagna and pizzas for a large party. Her lasagna recipe calls for 1 1/4 cups of tomato paste, and her pizza recipe uses 1/2 cup of tomato paste per pizza. She will double her lasagna recipe and make 5 pizzas. Write and evaluate an expression for how many 3/4- cup cans of tomato paste she will need in all.

Answer:

The evaluate and for how many 3/4-cup cans of tomato she need in all is 20/3

Step-by-step explanation:

Step 1

From the question, we are told that:

1 single lasgna recipe uses: 1 1/4 cups of tomato paste = 5/4 cups

If she doubles her recipe, the number of cups of tomato paste =

2 × 5/4 cups of tomato paste

= 10/ 4 = 5/2 cups of tomato pastes

Step 2

From the question, we are told that:

1 Pizza recipe = 1/2 cup of tomato pastes

5 Pizza =

5 × 1/2 cup of tomato paste

= 5/2 cups of tomato paste

Steps 3

The total number of cups of tomato paste Jada will use in making double lasagna and 5 pizzas is calculated as

= 5/2 + 5/2

= (5 + 5)/ 2

= 10/2

= 5 cups.

Step 4

We are asked to evaluate how many 3/4 -cup cans of tomato she need in all.

This means we should find how many 3/4 - cup cans can be found in the total number of cups of tomato paste that Jada used.

Total number of cups that Jada used = 5 cups of tomato paste

The number of 3/4-cup cans in 5 cups is calculated as:

5 ÷ (3/4)

= 5 × 4/3

= 20/3

Therefore, the evaluate and for how many 3/4-cup cans of tomato she need in all is 20/3

8 0

2 years ago

Use Gauss's Law to find the charge contained in the solid hemisphere x2 + y2 + z2 ≤ a2, z ≥ 0, if the electric field is E(x, y,

Anit [1.1K]

Answer: $\frac{16}{3}$ π $a^{3}$ . 

Given:

$x^{2}+y^{2}+z^{2} \leq a^{2}, z \geq 0$

Using Gauss's Law = ∫∫s E ·dS

= ∫∫∫ div E dV,

⇒ Divergence (Gauss') Theorem

= ∫∫∫ (1+1+6) dV

= 8×(volume of the hemisphere, radius "a")

= 8× ( $\frac{1}{2}$ )(4/3)π $a^{3}$

= $\frac{16}{3}$ π $a^{3}$ . 

6 0

2 years ago

. For each of these intervals, list all its elements or explain why it is empty. a) [a, a] b) [a, a) c) (a, a] d) (a, a) e) (a,

Eva8 [605]

Answer:

Elements are of the form

(i) $[a,a]=\{[x,y] : a\leq x\leq a, a\leq y\leq a; a\in \mathbb R\}$

(ii) $[a,b)=\{[x,y) :a\leq x$

(iii) $(a,a]=\{(x,y] :a$

(iv) $(a,a)=\{(x,y): a$

(v) (a,b) where a>b= $\{(x,y) : a>x>b,a>y>b;a>b,a,b \in \mathbb R\}$

(vi) [a,b] where a>b= $\{[x,y] : a\geq x\geq b,a\geq y\geq b;a>b,a,b \in \mathbb R\}$

Step-by-step explanation:

Given intervals are,

(i) [a,a] (ii) [a,a) (iii) (a,a] (iv) (a,a) (v) (a,b) where a>b (vi) [a,b] where a>b.

To show all its elements,

(i) [a,a]

Imply the set including aa from left as well as right side.

Its elements are of the form.

$\{[a,a] : a\in \mathbb R\}=\{[0,0],[1, 1],[-1,-1],[2,2],[-2,-2],[3,3],[-3,-3],........\}$

Since there is a singleton element a of real numbers, this set is empty.

Because there is no increment so if $a\in \mathbb R$ then the set [a,a] represents singleton sets, and singleton sets are empty so is [a,a].

(ii) [a,a)

This means given interval containing a by left and exclude a by right.

Its elements are of the form.

$[ 1, 1),[-1,-1),[2,2),[-2,-2),[3,3),[-3,-3),........$

Since there is a singleton element a of real numbers withis the set, this set is empty.

Because there is no increment so if $a\in \mathbb R$ then the set [a,a) represents singleton sets, and singleton sets are empty so is [a.a).

(iii) (a,a]

It means the interval not taking a by left and include a by right.

Its elements are of the form.

$( 1, 1],(-1,-1],(2,2],(-2,-2],(3,3],(-3,-3],........$

Since there is a singleton element a of real numbers, this set is empty.

Because there is no increment so if $a\in \mathbb R$ then the set (a,a] represents singleton sets, and singleton sets are empty so is (a,a].

(iv) (a,a)

Means given set excluding a by left as well as right.

Since there is a singleton element a of real numbers, this set is empty.

Its elements are of the form.

$( 1, 1),(-1,-1],(2,2],(-2,-2],(3,3],(-3,-3],........$

Because there is no increment so if $a\in \mathbb R$ then the set (a,a) represents singleton sets, and singleton sets are empty, so is (a,a).

(v) (a,b) where a>b.

Which indicate the interval containing a, b such that increment of x is always greater than increment of y which not take x and y by any side of the interval.

That is the graph is bounded by value of a and it contains elements like it we fixed a=5 then,

$(a,b)=\{(5,0),(5,1),(5,2).....\}$ e.t.c

So this set is connected and we know singletons are connected in $\mathbb R$ . Hence given set is empty.

(vi) [a,b] where $a\leq b$ .

Which indicate the interval containing a, b such that increment of x is always greater than increment of y which include both x and y.

That is the graph is bounded by value of a and it contains elements like it we fixed a=5 then,

$[a,b]=\{[5,0],[5,1],[5,2].....\}$ e.t.c

So this set is connected and we know singletons are connected in $\mathbb R$ . Hence given set is empty.

8 0

2 years ago