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Vesna [10]
2 years ago
13

in september 2016, the cost of gasoline in Berlin was around 1.25 euros per liter. what would the equivalent cost be in u.s. dol

lars per gallon?​
Mathematics
2 answers:
patriot [66]2 years ago
8 0

Answer:

1.48

Step-by-step explanation:

AnnZ [28]2 years ago
4 0

Answer:

roughly 1.50

Step-by-step explanation:

1 euro was 1.08 usd in 2016. common sense it's around 1.50

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One week, Claire earned $272.00 at her job when she worked for 17 hours. If she is paid the same hourly wage, how many hours wou
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Answer: 448 hours

Step-by-step explanation:

272 divided by 17 = hourly wage

hourly wage= 16$

448 divided by 16 = 28 weeks

28 x 16= 448 hours

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2 years ago
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Find three different irrational numbers between 0.13 and 0.14
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Answer:0.13468995325789542.....

0.135789075421345688....

0.136800865431234668...

Step-by-step explanation:

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m∠3 is (3x + 4)° and m∠5 is (2x + 11)°. Angles 3 and 5 are . The equation can be used to solve for x. m∠5 = °
ratelena [41]

I just did this question!

Answers:

1) <em>same side interior angles</em>

2) (3x+4)+(2x+11) = 180

3) 77


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2 years ago
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Courtney has a total of 88 stamps worth $15.56. Some are 25 cent stamps and some 2 cent stamps. How many of each does she have
Oksi-84 [34.3K]
<span>88 stamps -------------------- >  $15.56
A------------------------------>number of  </span>stamps ------------ ><span>25 cent
B----------------------------- > </span>number of  stamps ------------ >2 cent

A+B=88------------------ > A=88-B
0.25A+.02B=15.56
resolving
0.25(88-B)+0.02B=15.56
22-0.25B+0.02B=15.56
-0.23B=-6.44----------------------- > B=28 stamps of 2 cent
A=88-B-- >88-28=60------------- > A=60 stamps of 25 cent
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2 years ago
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Consider a prolific breed of rabbits whose birth and death rates, β and δ, are each proportional to the rabbit population P = P(
KonstantinChe [14]

Answer:

(P(t)) = P₀/(1 - P₀(kt)) was proved below.

Step-by-step explanation:

From the question, since β and δ are both proportional to P, we can deduce the following equation ;

dP/dt = k(M-P)P

dP/dt = (P^(2))(A-B)

If k = (A-B);

dP/dt = (P^(2))k

Thus, we obtain;

dP/(P^(2)) = k dt

((P(t), P₀)∫)dS/(S^(2)) = k∫dt

Thus; [(-1)/P(t)] + (1/P₀) = kt

Simplifying,

1/(P(t)) = (1/P₀) - kt

Multiply each term by (P(t)) to get ;

1 = (P(t))/P₀) - (P(t))(kt)

Multiply each term by (P₀) to give ;

P₀ = (P(t))[1 - P₀(kt)]

Divide both sides by (1-kt),

Thus; (P(t)) = P₀/(1 - P₀(kt))

4 0
2 years ago
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