It is 141.4 centimetres. This is because the circumference is obtained by multiplying pi with the diameter.
Answer:
A Type II error is when the null hypothesis is failed to be rejected even when the alternative hypothesis is true.
In this case, it would represent that the new program really increases the pass rate, but the sample taken is not enough statistical evidence to prove it. Then, the null hypothesis is not rejected.
The consequence is that the new method would be discarded (or changed) eventhough it is a real improvement.
Step-by-step explanation:
Running 2 miles at 8:15 per mile takes 16:30 minutes.
Running 3 miles at 7:12 per mile takes 21:36 minutes.
The total running time is 16:30 + 21:36 = 38:06 minutes. That length of time after 6:52 am is 7:30:06 am.
You get home for breakfast at 6 seconds past 7:30 am.
Answer:
- length: 14 feet , width: 43 feet, or
- length: 86 feet, width: 7 feet
Both solutions are valid.
Explanation:
1. First assumption is that the shape of the fence is <u>rectangular</u>.
2. Second, assum the length parallel to the wall measure y feet, so the other two lengths, y, together with x will add up 100 feet
3. The, the area of the fence will be:
- length × width = xy = 600
4. Now you have two equation with two variables which you can solveL
- Solve for y in the first equation: y = 100 - 2x
- Substitute the value of y into the second equation: x (100 - 2x) = 600
5. Solve the last equation by completing squares:
- Distributive property: 100x - 2x² = 600
- Divide both sides by - 1: 2x² - 100x = - 600
- Divide both sides by 2: x² - 50x = -300
- Add the sequare of the half of 50 to both sides: x² - 50x + 625 = 325
- Factor the left side: (x - 25)² = 325
- Square root both sides: x - 25 = ± 18.028
- Clear x: x = 25 ± 18.028
- x = 43.028 ≈ 43 or x = 6.972 ≈ 7
Both values are valid,
If x = 43 , then y = 600/43 = 14
If x = 7, then y = 600/7 = 86
Thus, the lenght and width of the fence may be:
- 43 feet (width) and 14 feet (length), or
- 7 feet (width) and 86 feet (length).
